Answer: part a) both the tension and gravity vectors will be pointing downwards.
part b) the tension vector will be pointing upwards and the gravity will be pointing downwards.
Explanation:
part a) Since you are looking at the FBD for the steel cable here, the tension will be pointing downwards because the girder is hung from the cable which creates a downwards tension. Gravity will always point downwards, to the ground.
part b) Since you are looking at the FBD for the girder here, the tension will be pulled upwards because the cable is weighted which creates an upwards tension. Gravity will always point downwards, to the ground.
Sorry for the poor explanation, but hopefully this makes sense.
Answer:
the initial velocity of the car is 12.04 m/s
Explanation:
Given;
force applied by the break, f = 1,398 N
distance moved by the car before stopping, d = 25 m
weight of the car, W = 4,729 N
The mass of the car is calculated as;
W = mg
m = W/g
m = (4,729) / (9.81)
m = 482.06 kg
The deceleration of the car when the force was applied;
-F = ma
a = -F/m
a = -1,398 / 482.06
a = -2.9 m/s²
The initial velocity of the car is calculated as;
v² = u² + 2ad
where;
v is the final velocity of the car at the point it stops = 0
u is the initial velocity of the car before the break was applied
0 = u² + 2(-a)d
0 = u² - 2ad
u² = 2ad
u = √2ad
u = √(2 x 2.9 x 25)
u =√(145)
u = 12.04 m/s
Therefore, the initial velocity of the car is 12.04 m/s
The ion has a charge of 1 +.
A neutral ion would have the same number of protons and neutrons. The neutrons have no charge (they're neutral) so they don't matter when it comes to the charge of an ion. This ion has 30 protons (+) and 29 electrons (-). There is 1 more proton than there are electrons so the ion has a charge of 1 +.
I am pretty sure it’s all the above
Answer:
d = 1.27m
Explanation:
Given m = 8.2×10-26kg, v = 1.1×10⁶m/s, q = +5e = 5×1.6×10‐¹⁹ C.
E = 49kN/C = 49000N/C
The displacement is given by
d = 1/2× mv²/qE = 1/2 × 8.2×10-²⁶ × (1.1×10⁶)²/(5×1.6×10-¹⁹ ×49000) = 1.27m
