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3 years ago

How many grams of lead sulfide from when 10.0 g of lead are heated with 3.0 g of sulfur

Chemistry

1 answer:

zaharov [31]3 years ago

4 0

The reaction forms 11.5 g PbS.

We have the masses of two reactants, so this is a limiting reactant problem.

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.

Step 1. Gather all the information in one place with molar masses above the formulas and everything else below them.

M_r: 207.2 32.06 239.28

Pb + S → PbS

Mass/g: 10.0 3.0

Step 2. Calculate the moles of each reactant

Moles of Pb = 10.0 g Pb × (1 mol Pb /207.2 g Pb) = 0.048 26 mol Pb

Moles of S = 30 g S × (1 mol S/32.06 g S) = 0.9357 mol S

Step 3. Identify the limiting reactant

Calculate the moles of PbS we can obtain from each reactant.

From Pb: Moles of PbS = 0.048 26 mol Pb × (1 mol PbS/1 mol Pb )

= 0.048 26 mol PbS

From S: Moles of S = 0.9357 mol S × (1 mol PbS/1 mol S) = 0.9357 mol PbS

Pb is the limiting reactant because it gives the smaller amount of PbS.

Step 4. Calculate the mass of PbS.

Mass = 0.048 26 mol PbS × (239.28 g PbS/1 mol PbS) = 11.5 g PbS

The reaction produces 11.5 g PbS.

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What is the ratio of the magenta phenolphthalein concentration to the colorless phenolphthalein concentration ([magenta phenolph

lilavasa [31]

Answer:

$\frac{[magenta\ phenolphthalein]}{[colorless\ phenolphthalein]}=31.62$

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:

$pH=pKa+\log\frac{[base]}{[acid]}$

Where Ka is the dissociation constant of the acid.

pKa of phenolphthalein = 9.40

pH = 10.9

So,

$10.9=9.40+\log\frac{[magenta\ phenolphthalein]}{[colorless\ phenolphthalein]}$

$\frac{[magenta\ phenolphthalein]}{[colorless\ phenolphthalein]}=31.62$

4 0

3 years ago

In the following reaction, how many moles of CO2 will form if 10 moles of C3H4 are reacted? How many moles of O2 will also be co

umka2103 [35]

Answer:

40 moles of O₂

30 moles of CO₂

Explanation:

Given parameters:

Number of moles of C₃H₄ = 10moles

Unknown:

Number of moles of CO₂ = ?

Solution:

The number of moles helps to understand and make quantitative measurements involving chemical reactions.

We start by solving this sort of problem by ensuring that the given equation is properly balanced;

C₃H₄ + 4O₂ → 3CO₂ + 2H₂O

We can clearly see that all the atoms are conserved.

Now, we work from the known to unknown. We know the number of moles of C₃H₄ to be 10moles;

1 mole of C₃H₄ reacted with 4 moles of O₂

10 moles of C₃H₄ will react with 10 x 4 = 40moles of O₂

1 mole of C₃H₄ will produce 3 moles of CO₂

10 moles of C₃H₄ will produce 10 x 3 = 30moles of CO₂

4 0

3 years ago

What your events made Gautam Buddha to go in search of the truth?

Dafna11 [192]

Answer:

The Buddha (also known as Siddhartha Gotama or Siddhārtha Gautama[note 3] or Buddha Shakyamuni) was a philosopher, mendicant, meditator, spiritual teacher, and religious leader who lived in Ancient India (c. 5th to 4th century BCE).[5][6][7][note 4] He is revered as the founder of the world religion of Buddhism, and worshipped by most Buddhist schools as the Enlightened One who has transcended Karma and escaped the cycle of birth and rebirth.[8][9][10] He taught for around 45 years and built a large following, both monastic and lay.[11] His teaching is based on his insight into duḥkha (typically translated as "suffering") and the end of dukkha – the state called Nibbāna or Nirvana.

The Buddha was born into an aristocratic family in the Shakya clan but eventually renounced lay life. According to Buddhist tradition, after several years of mendicancy, meditation, and asceticism, he awakened to understand the mechanism which keeps people trapped in the cycle of rebirth. The Buddha then traveled throughout the Ganges plain teaching and building a religious community. The Buddha taught a middle way between sensual indulgence and the severe asceticism found in the Indian śramaṇa movement.[12] He taught a spiritual path that included ethical training and meditative practices such as jhana and mindfulness. The Buddha also critiqued the practices of Brahmin priests, such as animal sacrifice.

A couple of centuries after his death he came to be known by the title Buddha, which means "Awakened One" or "Enlightened One".[13] Gautama's teachings were compiled by the Buddhist community in the Suttas, which contain his discourses, and the Vinaya, his codes for monastic practice. These were passed down in Middle-Indo Aryan dialects through an oral tradition.[14][15] Later generations composed additional texts, such as systematic treatises known as Abhidharma, biographies of the Buddha, collections of stories about the Buddha's past lives known as Jataka tales, and additional discourses, i.e, the Mahayana sutras.

Explanation:

8 0

3 years ago

2. HOW MUCH HEAT IS REQUIRED TO BE RELEASED WHEN

jarptica [38.1K]

Answer: -112200J

Explanation:

The amount of heat (Q) released from an heated substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = ?

Mass of water vapour = 30.0g

C = 187 J/ G°C

Φ = (Final temperature - Initial temperature)

= 100°C - 120°C = -20°C

Then apply the formula, Q = MCΦ

Q = 30.0g x 187 J/ G°C x -20°C

Q = -112200J (The negative sign does indicates that heat was released to the surroundings)

Thus, -112200 joules of heat is released when cooling the superheated vapour.

5 0

4 years ago

WILL MARK BRAINLIEST

den301095 [7]

The answer is C. Life
Hope this helps! :)

7 0

3 years ago