Molar mass of MgCO3 is 84.313 g/mol
You can calculate this from data on the periodic table:
Molar mass Mg = 24.305g/mol
molar mass C = 12.011g/mol
molar mass O = 15.999g/mol mass 3 mol = 47.997g
Total = 84.313g/mol
Mass to be used in 1.2L of 1.5M solution = 84.313g * 1.2L * 1.5mol /L = 151.763g
I have not taken significant figures into account
The balanced equation you provide is not necessary in this calculation
His strict imposition of autocratic rule was supported by his appointment by the King, who otherwise was not directly involved.
Explanation:
Andros’ imposition of Episcopalian worship in the Old South Meeting house, Boston his vigorous enforcement of the Navigation Acts.
He had earned the enmity of the local populace by enforcing the restrictive Navigation Acts.
He had infuriated Puritans in Boston by promoting the Church of England, which was rejected by many Nonconformist New England colonists.
When news of the overthrow of James II (1688) reached Boston, the colonists revolted, deposing Andros and imprisoning him.
His requirement that landholders take out new land patents and his limitations upon town meetings and rights of local taxation all aroused sharp resentment in colonial America.
Answer:
63.546
Explanation:
The Average atomic mass is calculated using the formula:
sum of the product of the atomic masses and their relative abundances all divided by 100 or total abundance
<u>Answer:</u> The correct answer is Option A.
<u>Explanation:</u>
A catalyst is defined as the substance which increases the rate of the reaction without actually participating in the reaction.
This substance decreases the activation energy of the reactants, so as to proceed the reaction at a faster rate by increasing their effective collisions.
It does not affect the concentration of the reactants.
For the given reaction:
If we add NO, which is acting as a catalyst will increase the rate of the reaction to produce the products which is 
Hence, the correct answer is Option A.
<span>Ionization energy (IE) is the amount of energy required to remove an electron.
If you observe the IEs sequentially, there is a large gap between the 2nd and 3rd. This suggests it is difficult to remove more than 2 two electrons. Elements that lose two electrons to become more stable are found in the Group 2A (2 representing the number of electrons in the outermost valence shell).</span>
