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3 years ago

Whick of the following quantities are vectors?

Physics

1 answer:

Rufina [12.5K]3 years ago

3 0

Velocity and displacement are vectors. (A and D)

Temperature, volume, and height aren't.

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When a current of 0.015 A passes through human body at 240 volts p.d it<br><br>causes

geniusboy [140]

Explanation:

Given that,

Current, I = 0.015 A

Voltage, V = 240 volts

We need to find the resistance. Using Ohm's law we can find it as follows :

$V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{240}{0.015}\\\\R=16000\ \Omega$

So, When a current of 0.015 A passes through human body at 240 volts p.d it causes 16000 ohms of resistance.

3 0

3 years ago

A geothermal plant has been built in a location. Which of these is the most likely benefit of the geothermal plant in this locat

kramer

Answer:

Explanation:

A and B are not true and D is a disadvantage

4 0

3 years ago

What factors does weight depend on?

Virty [35]

Answer:

m, g

Explanation:

G=m.g

m mass

g gravity

6 0

3 years ago

The area of the piston to the master cylinder in a hydraulic braking system of a car is 0.6 square inches. If a force of 5.6 lb

balu736 [363]

Answer:

16.8 lb is the force on the brake pad of one wheel.

Explanation:

Force applied on the piston = $F_1=5.6 lb$

Area of the piston = $A_1=0.6 inches^2$

Force applied on the brakes = $F_2$

Area of the brakes = $A_2=1.8 inches^2$

Applying Pascal's law: 'For an incompressible fluid pressure at one surface is equal to the pressure at other surface'.

$\frac{F_1}{A_2}=\frac{F_2}{A_2}$

$F_2=\frac{5.6 lb\times 1.8 inhes^2}{0.6 inches^2}=16.8 lb$

16.8 lb is the force on the brake pad of one wheel.

5 0

4 years ago

A runner is moving at a constant speed of 8.00 m/s around a circular track. If the distance from the runner to the center of the

Genrish500 [490]

Answer: Last option

2.27 m/s2

Explanation:

As the runner is running at a constant speed then the only acceleration present in the movement is the centripetal acceleration.

If we call a_c to the centripetal acceleration then, by definition

$a_c =w^2r = \frac{v^2}{r}$

in this case we know the speed of the runner

$v =8.00\ m/s$

The radius "r" will be the distance from the runner to the center of the track

$r = 28.2\ m$

$a_c = \frac{8^2}{28.2}\ m/s^2$

$a_c = 2.27\ m/s^2$

The answer is the last option

3 0

4 years ago