Answer:
All of the above.
Explanation:
In positive deviation from Raoult's Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.
When a solution is non ideal then it shows positive or negative deviation.
Let two solutions A and B to form non- ideal solutions.let the vapour pressure of component A is
and vapour pressure of component B is
.
= Vapour pressure of component A in pure form
= Vapour pressure of component B in pure form
=Mole fraction of component A
=Mole fraction of component B
The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.
,
Therefore, 
Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.
Hence, option a,b,c and d are true.
The answer is B because the more ions the more electrolytes it has
Answer:
The best answer would be:
C. The scientific method was followed because the experiment tested the hypothesis and produced reliable results.
Explanation:
The purpose of an experiment is to test the hypothesis. It is true that having an experimental group and a control group was following the scientific method but the data gathering and documentation was also part of the scientific method. So the best answer would be C.
Writing the question is not necessary. It is merely part of forming a hypothesis. The scientific method does not require many scientists to perform the experiment, but it does require that the experiment be repeatable, so it can be tested again.
False it can only be one to take place
<h3>
Answer:</h3>
300 kPa
<h3>
Explanation:</h3>
Concept tested: Gas Laws (Combined gas law)
Initial pressure, P₁ = 100 kPa
Initial temperature,T₁ = 27°C
But, K = °C + 273, therefore, T₁ = 300 K
Initial volume, V₁ = 900 L
New temperature, T₂ = -73°C
= -73°C + 273
= 200 K
New volume, V₂ = 200 L
We are required to calculate the new pressure, P₂
- To find the new pressure of the gas, we are going to use the combined gas law;
- Combined gas law combines both Charles's law and Boyle's law.
- According to the combined gas law;
P₁V₁/T₁ = P₂V₂/T₂
- To calculate the new Pressure, P₂, we rearranging the formula;
P₂ =(P₁V₁T₂) ÷ (V₂T₁)
Therefore;
P₂ = (100 kPa × 900 L × 200 K) ÷ (200 L × 300 K)
= 300 kPa
Therefore, a pressure of 300 kPa must be applied.