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-Dominant- [34]
3 years ago
15

Pure water and pure salt are poor conductors of electricity. When salt is dissolved in water, the resulting solution conducts el

ectricity well. Which statement explains why this occurs with these substances?
The process of dissolving makes the electrons in their atoms free to move

The process of dissolving makes the atoms in them free to move

The process of dissolving makes the electrons in their atoms more closely bound

The process of dissolving makes the atoms in them more closely bound to each other
Chemistry
2 answers:
notsponge [240]3 years ago
6 0

Answer:the process of dissovlving makes the ecectrons in their atoms more closely bound

Explanation:

thats what my lesson said

castortr0y [4]3 years ago
4 0

Answer:

you are right

Explanation:

it sounds good

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Positive Deviation from Raoult's Law occurs when the vapour pressure of component is greater than what is expected in Raoult's L
8090 [49]

Answer:

All of the above.

Explanation:

In positive deviation from Raoult's  Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.

When a solution is non ideal then it shows positive or negative deviation.

Let two solutions A and B to form non- ideal solutions.let the vapour pressure  of component A is P_A and vapour pressure of component B is P_B.

P^0_A= Vapour pressure of component A in pure form

P^0_B= Vapour pressure of component B in pure form

x_A=Mole fraction of component A

x_B==Mole fraction of component B

The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.

P_A >P^0_A\cdot x_A,P_B>P^0_B\cdot x_B

Therefore, P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B

Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.

Hence, option a,b,c and d are true.

6 0
3 years ago
Why would an aqueous solution of a strong electrolyte conduct electricity better than an aqueous solution of a weak electrolyte?
Virty [35]
The answer is B because the more ions the more electrolytes it has
4 0
4 years ago
Read 2 more answers
How was or wasn't the scientific method followed in this experment
Andreas93 [3]

Answer:

The best answer would be:

C. The scientific method was followed because the experiment tested the hypothesis and produced reliable results.

Explanation:

The purpose of an experiment is to test the hypothesis. It is true that having an experimental group and a control group was following the scientific method but the data gathering and documentation was also part of the scientific method. So the best answer would be C.

Writing the question is not necessary. It is merely part of forming a hypothesis. The scientific method does not require many scientists to perform the experiment, but it does require that the experiment be repeatable, so it can be tested again.

3 0
4 years ago
Easy Help Please!!!!!!
IRISSAK [1]
False it can only be one to take place
5 0
3 years ago
A 900 liter supply of xenon gas is held at 27 °C and 100 kPa. When the temperature is lowered to -73
svet-max [94.6K]
<h3>Answer:</h3>

300 kPa

<h3>Explanation:</h3>

Concept tested: Gas Laws (Combined gas law)

Initial pressure, P₁ = 100 kPa

Initial temperature,T₁ = 27°C

But, K = °C + 273, therefore, T₁ = 300 K

Initial volume, V₁ = 900 L

New temperature, T₂ = -73°C

                                   = -73°C + 273

                                   = 200 K

New volume, V₂ = 200 L             

We are required to calculate the new pressure, P₂

  • To find the new pressure of the gas, we are going to use the combined gas law;
  • Combined gas law combines both Charles's law and Boyle's law.
  • According to the combined gas law;

P₁V₁/T₁ = P₂V₂/T₂

  • To calculate the new Pressure, P₂, we rearranging the formula;

P₂ =(P₁V₁T₂) ÷ (V₂T₁)

Therefore;

P₂ = (100 kPa × 900 L × 200 K) ÷ (200 L × 300 K)

   = 300 kPa

Therefore, a pressure of 300 kPa must be applied.

6 0
4 years ago
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