Answer:To find S, the number of shared
electrons, recall that
S = N-A
Explanation:UwU
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<h2>
Answer:</h2>
Valance electrons can be determined by <u>Group</u> on the periodic table
<h2>
Explanation:</h2>
- Valence electrons are the electrons present in the outermost shell of an atom. We can determine the total number of valence electrons present in an atom by checking at its Group in which it is placed in the periodic table. For example, atoms in Groups 1 the number of valence electron is one and for group 2 the number of valence electrons is 2.
- The groups have number of valance electrons as follow:
Group 1 - 1 valence electron.
Group 2 - 2 valance electrons.
Group 13 - 3 valence electrons.
Group 14 - 4 valance electrons.
Group 15 - 5 valence electrons.
Group 16 - 6 valence electrons.
Group 17 - 7 valence electrons.
Group 18 - 8 valence electrons.
Result: No of valence electron can be determined by the group no. of the element.
Answer:
The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.
Explanation:
Balanced equation is 2 H + Cl2 = 2 HCl.
First thing, convert grams to moles via using molar mass.
Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.
Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.
Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.
If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.
If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.
Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.
Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.
Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.
0.992 mol x 36.4609 g / 1 mol = 36.175 g.
