**Answer:**

A single force, which is acting at angle θ from a horizontal axis, can be resolved into components which act along the perpendicular axis.

Consider the perpendicular axis x and y, where x represents the horizontal axis and y represents vertical axis.

The Force is resolved into 2 parts, one acts along x-axis and is represent by X. The other acts along y-axis and is represented by Y.

From the diagram we can see that the Force and its components X and Y makes up a right angles triangle, where θ is the angle from the x-axis

<h3 /><h3>Find X:</h3>

We know that:

cosθ = Base/Hypotenuse

cosθ = X/F

**X = Fcosθ**

<h3>Find Y:</h3>

We know that:

sinθ = Perpendicular/Hypotenuse

sinθ = Y/F

**Y = Fsinθ**

<h3>Relation of Force and its Components:</h3>

Force F can be represent by:

**F = Fcosθ (along x-axis) + Fsinθ (along y-axis)**

As they form a right angled triangle, we can use Pythagoras Theorem to show the relation between Force and its components.

Hypotenuse² = Base² + Perpendicular²

F² = X² + Y²

F² = (Fcosθ)² + (Fsinθ)²

Where θ can be found by using any of the trignometric functions.

**Answer:**

175.99.136.0

**Explanation:**

175.99.138.0/21

Step 1: convert both the ip and the subnet mask to binary format

175.99.138.0 - 10101111.1100011.10001010.00000000

/21 : 255.255.248.0 - 11111111.11111111.11111000.00000000

step 2: perform the bitwise AND operation

In an AND operation, a result of 1 can only be gotten when both inputs are 1. Otherwise, the result will be 0.

10101111.1100011.10001010.00000000

11111111. 11111111. 11111000. 00000000

------------------------------------------------------

10101111. 1100011. 10001000. 00000000

step 3: convert the binary result back to base 10 number

10101111. 1100011. 10001000. 00000000

175.99.136.0

Beta testing is a final step software development ( which means before a product is posted for other people to see) it’s supposed to make sure the user likes it or what they think about it.

Hope this helps :)

**Answer:**

**Explanation:**

Given

diameter(d)=1.1 m

mean velocity(u)=50 cm/s

mass flow rate(m)=110 kg/s

where =density of fluid

Therefore specific gravity

Specific weight

specific volume