Answer:
The solution is given in the attachments.
I dont know is your papers main idea stated clearly?
<u></u>
has greater effect.
<u>Explanation</u>:

= Temperature of cold reservoir
= Temperature of hot reservoir
when
is decreased by 't',
= 

when
is increased by 'T'


Answer:
w = 10.437 kips
deflection at 1/4 span 20.83\E ft
at mid span = 1.23\E ft
shear stress 7.3629 psi
Explanation:
area of cross section = 18*76
length of span = 32 ft
moment = 334 kips-ft
we know that
moment = load *eccentricity
334 = w * 32
w = 10.437 kips
deflection at 1/4 span



= 20.83\E ft
at mid span



shear stress
