<span>Friction creates heat which in turn can lead to deviations from the original size and shape of a part.
</span>
<span>In water, naoh almost completely separates into na+ and oh- ions. thus, naoh is Stong base.
Strong bases and strong acids completely ionized in the water,So when NaOH is added into water, it is completely ionized and forms Na+ and OH- ions and it shows that it is a strong base.</span>
Answer:
364 K or 91°C
Explanation:
Applying,
V₁/T₁ = V₂/T₂................ Equation 1
Where V₁ = Initial Volume, V₂ = Final volume, T₁ = initial Temperature, T₂ = final Temperature.
make T₂ the subject of the equation,
T₂ = V₂T₁/V₁................. Equation 2
From the question,
Given: V₁ = 375 mL, V₂ = 500 mL, T₁ = 0.0°C = (273+0) K = 273 K
Substitute these values into equation 2
T₂ = (500×273)/375
T₂ = 364 K
T₂ = (364-273) °C = 91 °C
Answer:
Roxanne said it was because chlorine is highly electronegative and sodium has a low ionization energy and that the ions Na and cr both have full electron shells.
<h2>
Answer:</h2>
Option B. Potassium(K).
<h2>
Explanation:</h2>
Electronic configuration of the given elements are:
- Ca - [Ar] 4s²
- K - [Ar] 4s¹
- B - [He] 2s2 2p1
- Kr - [Ar] 3d¹⁰4s²4p⁶
- Krypton(K) have 36 electrons and it is a noble gas and hence all of its shells are completely filled with electrons and hence it will never loose electrons in normal conditions.
- Boron(B) have 5 electrons and 3 electrons in its outer shell. In order to attain a stable configuration it will loose 3 electrons and it is difficult to loose 3 electrons at a time for an atom.
- Calcium(Ca) have 20 electrons and 2 electrons in its outermost shell, in order to attain a stable configuration it will loose 2 electrons. it is quite difficult but easier than Boron.
- Potassium(K) have 21 electrons and 1 electron in its outermost orbit and in order to attain a stable configuration it will loose 1 electron. It is much easier to donate 1 electron than 2 or 3 electrons.
Result: Potassium will loose an electron most easily from the given elements.