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Contact [7]
3 years ago
10

The element silver exists in nature as two isotopes: 107Ag has a mass of 106.9051 u, and 109Ag has a mass of 108.9048 u. The ave

rage atomic mass of silver is 107.87 u. Calculate the relative abundance (as percentages) of the two silver isotopes.

Chemistry
1 answer:
Lilit [14]3 years ago
3 0

Answer:

107Ag has abundance of 51.7%

109Ag has abundance of 48.3%

Explanation: Please see attachment for explanation

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2 years ago
Neptune is 30 AU (astronomical units) from the sun. How long, in light minutes, would it take for light from the sun to reach Ne
shtirl [24]

Answer:

250 light minutes takes

Explanation:

1 astonomical unit is equal to 1.50x10¹¹m

The light travels at the speed of 3.0x10⁸m/s. That means in 1 second, travels 3.0x10⁸m. To solve this question we must find the distance of neptune to the sun in meters. In this way we can find the seconds (And minutes) that need the light to travel from the sun to neptune:

<em>Distance from Sun to neptune:</em>

30AU * (1.50x10¹¹m / 1AU) = 4.5x10¹²m

<em>Time transcurred:</em>

4.5x10¹²m * (1s / 3.0x10⁸m) = 15000s

15000s * (1min / 60s) =

<h3>250 light minutes takes</h3>

7 0
3 years ago
As a liquid is added to a beaker, the pressure exerted by the liquid on the bottom of the beaker does what
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So if you put a holo ball of paper in the water it sinks and as it sinks it gets smaller cuse pressure so it cuseus things to shrink cuse of pressure
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3 years ago
Type the correct answer in the box. Express the answer to two significant figures.
meriva

Delta enthalpy = 2x386-3x1x432-3x942=-3350kJ/mol

8 0
3 years ago
Read 2 more answers
A frying pan needs a Teflon coating of 1.00 mm in thickness to cover an area of 36.0 square inches. How many ounces of Teflon ar
Otrada [13]

Answer:

m = 0.659 ounce

Explanation:

It is given that,

The thickness of a Teflon coating is, d = 1 mm

Area of the coating, A = 36 inch²

The density of Teflon, d = 0.805 g/mL

We need to find ounces of Teflon are needed.

Firstly, find the volume of the Teflon needed,

1 inch² = 6.4516 cm²

36 inch² = 232.258 cm²

Density,

\rho=\dfrac{m}{V}

V is volume of the Teflon needed, V = Ad

So,

m=\rho V\\\\m=0.805\ g/cm^3\times 232.258\ cm^2 \times 0.1\ cm\\\\m=18.69\ g

Also, 1 gram = 0.035274 ounce

18.69 gram = 0.659 ounce

So, 0.659 ounces of Teflon are needed.

3 0
3 years ago
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