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Arte-miy333 [17]
3 years ago
13

Find the velocity and rate of flow of water through a rectangular channel of 6m wide and 3m deep when it's running full. The cha

nnel is having a bed slope of 1 in 2000. Take Chezy's coefficient, C=55
Engineering
1 answer:
Elza [17]3 years ago
5 0

Answer:

V = 1.5062 m/s

Explanation:

look to the photos

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Explain working of Laser Doppler Vibrometer with diagram.
Klio2033 [76]

Answer:

A laser-Doppler vibrometer  identifies the Doppler effect or shift of laser light reflected from the sample object

Explanation:

A laser-Doppler vibrometer (e.g. Micro Motion Analyzer 400 from Polytec) identifies the Doppler effect or shift of laser light reflected from the sample object .At a beam splitter, a laser beam is partitioned into a measuring beam  and a reference beam that deflects 90 ° upwards and transmit to the reference mirror "RM." Both beams come back to the beam splitter.

6 0
3 years ago
Which situation might cause potential hazards at a construction site?
nata0808 [166]

Answer:

D. protruding steel rebars .. #answerwithquality #BAL

5 0
3 years ago
Read 2 more answers
The bolts that attach a bracket to an industrial machine must each carry a static tensile load of 4 kN.
HACTEHA [7]

Answer:

M10 × 1.5

least number of threads is 4.3

Explanation:

given data

static tensile load = 4 kN = 4000 N

safety factor = 5

coarse‐thread metric = 5.8

solution

we know that proof load for 5.8  class is Sp = 380 MPa

so area of cross section is express as

area = \frac{force \times FOS}{Sp}    ......................1

area = \frac{4000 \times }{380}

area = 52.6  mm²

so by table at 58 mm² we can say we resist  M10 × 1.5

and

bolt tensile strength is express as

bolt tensile strength = nut shear strength    ......2

so here bolt tensile strength = At × Sy (bolt)    ...............3

and nut shear strength =  πd ( 0.75 t ) Sys

nut shear strength =   π × 10 × ( 0.75 t )  × 0.58  × \frac{2}{3}   × Sy(bolt)   ............4

so from equation 3 and 4 we get

t = 6.37 mm

and

for the pitch is = 1.5 mm

least number of threads is 4.3

8 0
3 years ago
BE-27 In regard to waste management laws, a boat of what length or greater (in feet) is required to have an oil discharge
anastassius [24]

Answer: 26 feet

Explanation:

Federal law requires that when a boat of 26ft or more is on lakes, rivers, or in the ocean 3 miles from shore, it should "prominently posted" placards about garbage as well as Oil Discharges stating that oil discharges are not allowed as well as what materials can and are prohibited from being thrown from the boat into the water.

Both placards should be permanently attached with a minimum size of 5*9 inches and made entirely of durable material.

I have attached an example of the placard.

6 0
4 years ago
Read 2 more answers
A wet cooling tower is to cool 60 kg/s of water from 40 to 33°C. Atmospheric air enters the tower at 1 atm with dry-and wet-bulb
AveGali [126]

Answer:

32.06m³/s

0.62kg/s

Explanation:

Using our psychometric chart, at T1 = 22°C and wet bulb = 16°C, we have

h1 = 45.6kj/kg

v1 = 0.85m³/kg

w1 = 0.00923

At T2 = 30°C, T3 = 40°C, T4 = 33°C

h2 = 96.1kj/kg

w2 = 0.02579

h3 = 168kj/kg

h4 = 138kj/kg

Using the mass for rate balances for water and air, we have

m'(a1) = m'(a2) = m'(a)

m'(3) - m'(4) = m'(a) [w2 - w1] = m'(m)

Now, we use the energy balance equation to solve for the needed mass, m'(a). Mass flow rate of water, m'3 = 60kg/s

0 = m'(a)h2 + m'4h4 - m'(a)h1 - m'3h3

0 = m'(a) [h2 - h1] + [-m'(a) {w2-w1} + m'3]h4 - m'3h3

m'(a) = [m'3(h3 - h4) ] / [ h2 - h1 - (w2 - w1)h4

m'(a) = [60(168-138)] / 96.1 - 45.6 - (0.02579 - 0.00923)168

m'(a) = 60*30 / 50.5 - 0.01656*168

m'(a) = 1800 / 47.72

m'(a) = 37.72kg/s

Volume flow rate = m'(a) * v1

Volume flow rate = 37.72 * 0.85

Volume flow rate = 32.06m³/s

Mass flow rate of make up water =

m'(m) = m'(a) [w2 - w1]

m'(m) = 37.72 [0.02579 - 0.00923]

m'(m) = 37.72 * 0.01656

m'(m) = 0.62kg/s

4 0
4 years ago
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