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Elena L [17]
3 years ago
7

How many different simple machines on a bike? If you can please name the class of lever,pulley etc.

Physics
1 answer:
amid [387]3 years ago
7 0

Answer:

there should be 4 2 levers and 2 wheels

Explanation:

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Kinetic energy is stored in a stretched rubber
IRISSAK [1]

Answer:

potential until released

4 0
3 years ago
Read 2 more answers
Which statements describe elliptical galaxies? *Select the two correct answers.*
Alecsey [184]

Elliptical galaxies are galaxies that are shaped like an ellipse. An ellipse is oval in shape, which means elliptical galaxies are oval in shape.

The <u>two correct statements</u> that describe elliptical galaxies are:

B. They are the most common galaxy type.

C. They typically contain very little gas and dust.

  • Elliptical galaxies are galaxies where you will find little or no gas and dust. The galaxies that are numerous in number are the elliptical galaxies.

  • In the elliptical galaxy, you can't find any <u>spiral component </u>in it.

Therefore, from the above explanation, we can see that <u>option B and C is the correct option.</u>

To learn more, visit the link below:

brainly.com/question/13645005

6 0
3 years ago
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Suppose that the Sun were to collapse from its current radius of about 700,000 km to a radius of only about 6000 km (about the r
Maksim231197 [3]

Answer:

Only there will be a change in density of sun.

Explanation:

As your question says only the radius of sun is decreased and there is no change in the mass. So it means that the center of gravity will be the same and as a result the gravitational force remains the same. Only the density of sun changes as it shrinks.

8 0
3 years ago
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A pitot tube system measures the static pressure in 50 cm diameter duct containing air (\rho\:=rho =1.1 kg/m3) as 97 kPa and the
erastova [34]

Answer:

The velocity in duct is 73.854 m/s.

Explanation:

Given that Pitot tube measuring velocity v in 50 cm diameter duct contain air of density 1.1 \frac{kg}{m^{3} }.

Also, P1 = Pressure in duct is 97kpa and P2 = Pressure at impact or stagnation point is 100kpa.

Using Bernoulli equation,

P+\frac{1}{2}\rho v^{2} +\rho gh=0

When air is flowing through duct,

97,000+\frac{1}{2}\rho v^{2} +\rho gh1=0

When air is at stagnation point.

1,00,000+0+\rho gh1=0

Comparing both the equation,

97,000+\frac{1}{2}\rho v^{2} +\rho gh1=1,00,000+\rho gh1

\frac{1}{2}\rho v^{2}=3000

0.55v^{2}=3000

v^{2}=5454.54

v=73.854 m/s.

Therefore, The velocity in duct is 73.854 m/s.

4 0
4 years ago
A 6.99-g bullet is moving horizontally with a velocity of +341 m/s, where the sign + indicates that it is moving to the right (s
Ratling [72]

Answer:

a). 1.218 m/s

b). R=2.8^{-3}

Explanation:

m_{bullet}=6.99g*\frac{1kg}{1000g}=6.99x10^{-3}kg

v_{bullet}=341\frac{m}{s}

Momentum of the motion the first part of the motion have a momentum that is:

P_{1}=m_{bullet}*v_{bullet}

P_{1}=6.99x10^{-3}kg*341\frac{m}{s} \\P_{1}=2.3529

The final momentum is the motion before the action so:

a).

P_{2}=m_{b1}*v_{fbullet}+(m_{b2}+m_{bullet})*v_{f}}

P_{2}=1.202 kg*0.554\frac{m}{s}+(1.523kg+6.99x10^{-3}kg)*v_{f}

P_{1}=P_{2}

2.529=0.665+(1.5299)*v_{f}\\v_{f}=\frac{1.864}{1.5299}\\v_{f}=1.218 \frac{m}{s}

b).

kinetic energy

K=\frac{1}{2}*m*(v)^{2}

Kinetic energy after

Ka=\frac{1}{2}*1.202*(0.554)^{2}+\frac{1}{2}*1.523*(1.218)^{2}\\Ka=1.142 J

Kinetic energy before

Kb=\frac{1}{2}*mb*(vf)^{2}\\Kb=\frac{1}{2}*6.99x10^{-3}kg*(341)^{2}\\Kb=406.4J

Ratio =\frac{Ka}{Kb}

R=\frac{1.14}{406.4}\\R=2.8x10^{-3}

3 0
4 years ago
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