Answer:
The minimum speed of the box bottom of the incline so that it will reach the skier is 8.19 m/s.
Explanation:
It is given that,
Mass of the box, m = 2.2 kg
The box is inclined at an angle of 30 degrees
Vertical distance, d = 3.1 m
The coefficient of friction, 
Using the work energy theorem, the loss of kinetic energy is equal to the sum of gain in potential energy and the work done against friction.
W is the work done by the friction.
v = 8.19 m/s
So, the speed of the box is 8.19 m/s. Hence, this is the required solution.
Potassium is the 19th element so it is B
B or D, one of these are the correct answer
When we say directly northeast that is equivalent
to 45˚ north of east.
First let us determine the north and east
components of the acceleration using cos and sin functions:<span>
North = 2.18 * sin 45
East = 2.18 * cos 45
<span>Then we set to determine the east component of the plane’s
displacement by calculating using the formula:
d = vi * t + ½ * a * t^2
d = 135 * 18 + ½ * 2.18 * cos 45 * 18^2
<span>d = 2430 + 353.16 * cos 45 = 2679.72 m</span>
Calculating for the north component:
North = ½ * 2.18 * sin 45 * 18^2 </span></span>
North = 249.72 m
Hence magnitude is:
Magnitude = sqrt (2679.72^2 + 249.72^2)
Magnitude = 2,691. 33 m<span>
</span>
Calculating for angle:
Tan θ = North ÷ East <span>
<span>Tan θ = 249.72 m ÷ 2679.72 m</span></span>
θ = 5.32°<span>
</span>
So the plane was flying at 2,691. 33 m at 5.32<span>°</span>
