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3 years ago

Which radioactive element is used to determine the absolute age of late pleistocene animal remains?

1 answer:

vladimir2022 [97]3 years ago

7 0

Carbon-14 is radioactive element is used to determine the absolute age of late pleistocene animal remains because it is abundant in organic matter. Its decay is first-order and its half-life has been determined to be 5730 years which means that after 5730 years, the amount of carbon−14 will be 1/2 of the initial amount.

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What is the density of a bar of soap with a mass of 715g, and a volume of 866cm3?

mihalych1998 [28]

Answer:

0.826 g/cm³

Explanation:

density = mass/volume

density = 715 g/866 cm³

density = 0.82564 g/cm³

Rounded to 3 significant figures: 0.826 g/cm³

4 0

3 years ago

How many moles of \ce{Fe2O3}FeX 2 OX 3 will be produced from 27.0 \text{ g}27.0 g27, point, 0, start text, space, g, end tex

ira [324]

Answer : The number of moles of $Fe_2O_3$ produced will be, 0.241 moles.

Solution : Given,

Mass of Fe = 27.0 g

Molar mass of $Fe$ = 56 g/mole

First we have to calculate the moles of $Fe$ .

$\text{ Moles of }Fe=\frac{\text{ Mass of }Fe}{\text{ Molar mass of }Fe}=\frac{27.0g}{56g/mole}=0.482moles$

Now we have to calculate the moles of $Fe_2O_3$

The balanced chemical reaction is,

$4Fe+3O_2\rightarrow 2Fe_2O_3$

From the reaction, we conclude that

As, 4 mole of $Fe$ react to give 2 mole of $Fe_2O_3$

So, 0.482 moles of $Fe$ react to give $\frac{0.482}{4}\times 2=0.241$ moles of $Fe_2O_3$

Thus, the number of moles of $Fe_2O_3$ produced will be, 0.241 moles.

6 0

3 years ago

I need some help please

Norma-Jean [14]

Answer:

the first one to the third box

the second one to the fourth box

the third one to second box

and the fourth one to the first box

Explanation:

5 0

3 years ago

What is the ph of a solution made by mixing 25.00 ml of 0.100 m hcl with 40.00 ml of 0.100 m koh? assume that the volumes of the

Digiron [165]

Answer: The HCl and KOH will react until one or the other is gone. As you have a larger volume of an equal concentration of HCl, the KOH will go first. moles HCl = 0.04000 L * 0.100 M = 0.00400 moles moles KOH = 0.02500 L * 0.100 M = 0.00250 moles moles HCl left = 0.00400 - 0.00250 = 0.00150 moles Your total volume is now 65.00 mL, so the [HCl] = 0.00150 moles / 0.06500 L = 0.0231 M = [H+] pH = -log [H+] = -log (0.0231) = 1.64

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3 years ago

A red car and a blue car collide. What would be an example of Locard's exchange principle in this situation?

Lelu [443]

Answer:

The blue car left paint on the red car

Explanation:

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3 years ago