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Setler79 [48]
1 year ago
6

Copper metal (Cu) reacts with silver nitrate (AgNO3) in aqueous solution to form Ag and Cu(NO3)2. The balanced chemical equation

is shown below. Cu 2AgNO3 Right arrow. Cu(NO3)2 2Ag The molar mass of Cu is 63. 5 g/mol. The molar mass of Ag is 107. 9 g/mol. What mass, in grams, of Ag is produced from a reaction of 31. 75 g of Cu? 26. 95 grams 107. 9 grams 215. 91 grams 431. 82 grams.
Chemistry
1 answer:
mars1129 [50]1 year ago
3 0

107.9 g of Ag is produced from a reaction of 31. 75 gram of Copper.

<h3>How we calculate mass from the moles?</h3>

Mass of any substance will be calculated from its moles as:

n = W/M, where

W = required mass

M= molar mas

Given chemical reaction is:

Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

From the stoichiometry of the reaction, it is clear that:

1 mole of Cu = produce 2 moles of Ag

Given mass of Cu = 31.75g

Molar mass of Cu = 63.5g/mol

Moles of Cu = 31.75g / 63.5g/mol = 0.5 moles

0.5 moles of Cu = produce 2×0.5 = 1 mole of Ag

Molar mass of Ag = 107.9g/mol

Required mass of Ag = 1mol × 107.9g/mol = 107.9 g

Hence, option (2) is correct i.e. 107.9 g of Ag is produced.

To know more about moles, visit the below link:

https://brainly.in/question/148570

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A person suffering from hyponatremia has a sodium ion concentration in the blood of 0.116 M and a total blood volume of 4.7 L .
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Explanation:

Normal moles of Na^{+} = volume × normal concentration

                              = 4.7 × 0.139 = 0.6533 mol

Moles of Na^{+} in hyponatremia blood = volume × hyponatremia concentration

                              = 4.7 × 0.116 = 0.5452 mol

Moles of NaCl to be added = moles of extra Na^{+} needed

                            = 0.6533 mol - 0.5452 mol = 0.1081 mol

Mass of NaCl = moles × molar mass of NaCl

                        = 0.1081 mol × 58.443

                        = 6.317g

                        = 6.32 g (approx)

Thus, we can conclude that mass of sodium chloride would need to be added to the blood is 6.32 g.                    

3 0
3 years ago
Using your knowledge of reagents that react with alkenes, what would be a reagent that you could use to check and see if the hyd
igomit [66]

Answer:

An halogen addition reaction, particularly bromine addition, could be used to check if the hydrogenation has completed.

Explanation:

The aim is to find a way to check if the hydrogenation process of an alkene has completed. So the logic should be use a reaction that needs the participation of the double bound of the alkene, and therefore shouldn't take place in the process has finished.

A simple organic reaction is the halogen addition reaction, which occur between the halogen molecule and the double bond of the alkene. Basically, the pi electrons of the double bond attacks a relatively electrophilic halogen atom following a mechanism that leads to the addition of two halogen atoms to the double bond. As a consequence the alkene transforms into an haloalkane.

Also, a commonly used halogen is bromine, as it has a reasonable reactivity and it has red colour, which allows to monitor the progression of the reaction.

Taking all this in account, we can say that using a bromine addition reaction to the alkene it's a good option to check the completion of the hydrogenation.

Note that the bromine will react only if the double bond is present. So, if the hydrogenation has completed, the reaction won't occur. Using bromine will be the best option, as it is red coloured. That means that is we add bromine to an incomplete hydrogenation, as it will react with the alkene, the colour should disappear.

In other words, to check if the hydrogenation reaction has completed, we should add bromine and see what happens to the colour. If it doesn't change, then the hydrogenation reaction has completed.

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The work function is the energy that must be supplied to cause the release of an electron from a photoelectric material. The cor
vladimir2022 [97]

Answer:

No photoelectric effect is observed for Mercury.

Explanation:

From E= hf

h= Plank's constant

f= frequency of incident light

Threshold Frequency of mercury= 435×10^3/ 6.6×10^-34 × 6.02×10^23

f= 11×10^14 Hz

The highest frequency of visible light is 7.5×10^14. This is clearly less than the threshold frequency of mercury hence no electron is emitted from the mercury surface

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