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2 years ago

You are grilling hamburgers for a neighborhood cookout. What type of energy transfer makes the grill marks on the hamburgers?

Physics

1 answer:

LekaFEV [45]2 years ago

8 0

Answer: Radiation

Explanation:

Radiation refers to the transfer of heat from one source to another material. The transfer of heat energy from the sun to the earth is called radiation. The grilling of the hamburgers is an example of the radiation as in grilling no direct heat is involved instead the radiations or flames beneath the grilling barbeque burn or grill the hamburgers. Fumes or flames of a charcoal transfer radiations to the grilling hamburgers.

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It is important to wear protective equipment in both practice and games.

Ede4ka [16]

Answer:

It is important to wear protective equipments during games and practices.

Explanation:

Practice is a review of what is about to happen in some time to come and with practice ,the future can be trusted.

During practice it is very important to use protective gears or equipments because without them, injuries and accidents are liable to occur.

During the major game it is also important to prevent accidents or big injuries as the equipments protect each vital part of the body.

4 0

3 years ago

The length of the student desk is measured using a

charle [14.2K]

Answer:

3 significant figures are in 1.02m

Explanation:

4 0

3 years ago

The ideal mechanical advantage of an inclined plane is 3.5, and its efficiency is 0.6. What is the mechanical advantage of the i

Nadya [2.5K]

Mechanical advantage = ideal mechanical advantage x efficiency = 3.5 x 0.6 = 2.1
The mechanical advantage of the inclined plane is 2.1

7 0

3 years ago

Please answer the following question

aleksklad [387]

Answer:

1. Light Bulb

2. A switch

3. A battery

4. Ammeter

5. Resistor

6. Voltmeter

4 0

3 years ago

A body falls from the top of the tower and during the last second of its fall it fall through 23mvfind height of tower.

DanielleElmas [232]

Answer:

39.7 m

Explanation:

First, we conside only the last second of fall of the body. We can apply the following suvat equation:

$s=ut+\frac{1}{2}at^2$

where, taking downward as positive direction:

s = 23 m is the displacement of the body

t = 1 s is the time interval considered

$a=g=9.8 m/s^2$ is the acceleration

u is the velocity of the body at the beginning of that second

Solving for u, we find:

$ut=s-\frac{1}{2}at^2\\u=\frac{s}{t}-\frac{1}{2}at=\frac{23}{1}-\frac{1}{2}(9.8)(1)=18.1 m/s$

Now we can call this velocity that we found v,

v = 18 m/s

And we can now consider the first part of the fall, where we can apply the following suvat equation:

$v^2-u^2 = 2as'$

where

v = 18 m/s

u = 0 (the body falls from rest)

s' is the displacement of the body before the last second

Solving for s',

$s'=\frac{v^2-u^2}{2a}=\frac{18.1^2-0}{2(9.8)}=16.7 m$

Therefore, the total heigth of the building is the sum of s and s':

h = s + s' = 23 m + 16.7 m = 39.7 m

7 0

3 years ago