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Tems11 [23]
2 years ago
11

A car is driven 110 km west and then 40 km southwest, how far is the car from the point of origin?

Physics
1 answer:
Margaret [11]2 years ago
8 0

Answer:

141.147 km

Explanation:

sin45=\frac{BD}{BC}\\\Rightarrow BD=BCsin45\\\Rightarrow BD=40\times sin45\\\Rightarrow BD=28.28\ km

Now, AE=BD also CD=BD as the angle B and C are equal

So, from Pythagoras theorem

AC² = AE²+(CD+DE)²

AC=\sqrt{AE^2+(CD+DE)^2}\\\Rightarrow AC=\sqrt{(40\times sin45)^2+(110+40\times sin45)^2}\\\Rightarrow AC=141.147\ km

Displacement of the car is 141.147 km

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