Answer:
option C
Explanation:
The correct answer is option C
Kinetic energy is the energy which is due to the motion of body.
Potential energy is the energy due to virtue of position of the object.
option A is not true because potential energy is due the position of the body
Option B should be the potential energy not kinetic energy.;
Option D is motion of individual molecule leads to kinetic energy not potential energy.
So, the correct answer is option is the covalent bonds of a sugar molecule is potential energy because of the position of bond.
Given:
L = 1 mH = 
H
total Resistance, R = 11 
current at t = 0 s,
= 2.8 A
Formula used:
Solution:
Using the given formula:
current after t = 0.5 ms = 
for the inductive circuit:
I =0.011 A
I’m going to use molasses as an example of a substance.
The mass and volume both change when changing the amount of molasses.
However, the density does not change. This is because the mass and volume increase at the same rate/proportion!
Even though there is more molasses (mass) in test tube A, the molasses also takes up more space (volume). Therefore, the spacing between those tiny particles that make up the molasses is constant (does not change).
The size or amount of a material/substance does not affect its density.
Answer:
T = 2 T₀
Explanation:
To answer this question let's write the expression for electrical conductivity
σ = n e2 τ / m*
The relationship with resistivity is
ρ = 1 /σ
Whereby the resistance
R = ρ L / A = 1 /σ L / A
We see that there is no explicit relationship between time and resistance, there is only a dependence on the life time (τ) that depends on the properties of the material, not on its diameter or length.
As also the average velocity or electron velocity of electrons is constant, the time to cross 2 mm in length is twice as long as the time to cross a mm in length
T = 2 T₀
<u>Answer:</u> The Young's modulus for the wire is 
<u>Explanation:</u>
Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.
The equation representing Young's Modulus is:
where,
Y = Young's Modulus
F = force exerted by the weight = 
m = mass of the ball = 10 kg
g = acceleration due to gravity = 
l = length of wire = 2.6 m
A = area of cross section = 
r = radius of the wire = 
(Conversion factor: 1 m = 1000 mm)
= change in length = 1.99 mm = 
Putting values in above equation, we get:
Hence, the Young's modulus for the wire is
