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Tems11 [23]
3 years ago
11

A car is driven 110 km west and then 40 km southwest, how far is the car from the point of origin?

Physics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

141.147 km

Explanation:

sin45=\frac{BD}{BC}\\\Rightarrow BD=BCsin45\\\Rightarrow BD=40\times sin45\\\Rightarrow BD=28.28\ km

Now, AE=BD also CD=BD as the angle B and C are equal

So, from Pythagoras theorem

AC² = AE²+(CD+DE)²

AC=\sqrt{AE^2+(CD+DE)^2}\\\Rightarrow AC=\sqrt{(40\times sin45)^2+(110+40\times sin45)^2}\\\Rightarrow AC=141.147\ km

Displacement of the car is 141.147 km

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Explanation:

The heart rate of the astronaut is 78.5 beats per minute, which means that the time between heart beats is 0.0127 min. This will be the time t measured by the moving observer. The time t' measured by the stationary Earth-based observer is given by

t' = \dfrac{t}{\sqrt{1 - \left(\dfrac{v^2}{c^2}\right)}}

a) If the astronaut is moving at 0.480c, the time t' is

t' = \dfrac{0.0127\:\text{min}}{\sqrt{1 - \left(\dfrac{0.2304c^2}{c^2}\right)}}

\:\:\:\:=0.0145\:\text{min}

This means that time between his heart beats as measured by Earth-based observer is 0.0145 min, which is equivalent to 69.1 beats per minute.

b) At v = 0.940c, the time t' is

t' = \dfrac{0.0127\:\text{min}}{\sqrt{1 - \left(\dfrac{0.8836c^2}{c^2}\right)}}

\:\:\:\:=0.0372\:\text{min}

So at this speed, the astronaut's heart rate is 1/(0.0372 min) or 26.9 beats per minute.

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3 years ago
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Ricardo, of mass 80 kg, and Carmelita, who is lighter, are enjoying Lake Merced at dusk in a 30 kg canoe. When the canoe is at r
Deffense [45]

Answer:

m=57.65 kg

Explanation:

Given Data

Ricardo mass m₁=80 kg

Canoe mass m₂=30 kg

Canoe Length L= 3 m

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When Canoe was at rest the net total torque is zero.

Let the center of mass is at x distance from the canoe center and it will be towards the Ricardo cause. So the toque around the center of mass is given as

m_{1}(L/2-x)=m_{2}x+m_{2}(L/2-x)

We have to find m₂.To find the value of m₂ first we need figure out the value of.As they changed their positions the center of mass moved to other side by distance 2x.

so

2x=40

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Substitute in the above equation we get

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