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aalyn [17]
3 years ago
9

¿Cuál es la frecuencia de rotación en la tierra?

Physics
2 answers:
Vitek1552 [10]3 years ago
8 0
La Tierra gira más y más lento
Movimientos de la Tierra Características
Periodo de rotación sideral 365,256 96 días
Período de rotación (día sideral) 0,997 258 días, o 23,93419 h
Velocidad de rotación (en el ecuador) 1 674,364 km/h
Periodo de precesión 25 765 anos
4 more
lina2011 [118]3 years ago
5 0

Answer:

frequency is approximately 11.5 µHz, or more exactly, 11.5740740e-6 Hz

Explanation:

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I feel that people hurt the land and are destroying. I think they aren't using the land for the right reasons.

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If a golf ball and a ping-pong ball both move with the same kinetic energy, which has the greater speed? 1. the golf ball 2. can
schepotkina [342]
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4 0
4 years ago
Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.0 kg gibbon
LiRa [457]

Answer:

241.8 N.

Explanation:

The force on branch provides a reaction to the ape's weight force plus the centripetal force needed to keep the gibbon in a circular motion of radius 0.60 m.

Centripetal force = mv^2/r

F = mg + mv²/r

F = m(g + v²/r)

where,

m = mass

= 9 kg

g = acceleration due to gravity

= 9.8 m/s²

v = 3.2 m/s

r = 0.60 m

F = 9 * (9.8 + 3.2²/0.60)

= 241.8 N.

3 0
3 years ago
A horizontal force of 750 N is needed to overcome the force of static friction between a level floor and a 250-kg crate. What is
loris [4]

Answer:

The acceleration of the crate is 1.82\ m/s^2.

Explanation:

Given that,

Force, F = 750 N

Mass of the crate, m = 250 kg

The coefficient of friction is 0.12.

We need to find the acceleration of the crate. The net force acting on the crate is given by :

F=ma\\\\F-f=ma

f is frictional force, f=\mu N=\mu mg

F-\mu mg=ma\\\\a=\dfrac{F-\mu mg}{m}\\\\a=\dfrac{750-0.12\times 250\times 9.8}{250}\\\\a=1.82\ m/s^2

So, the acceleration of the crate is 1.82\ m/s^2. Hence, this is the required solution.

4 0
3 years ago
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