The power of the machine is 50
Let <em>a</em> denote the airplane's velocity in the air, <em>g</em> its velocity on the ground, and <em>w</em> the velocity of the wind. (Note that these are vectors.) Then
<em>a</em> = <em>g</em> + <em>w</em>
and we're given
<em>a</em> = (325 m/s) <em>j</em>
<em>w</em> = (55.0 m/s) <em>i</em>
Then
<em>g</em> = - (55.0 m/s) <em>i</em> + (325 m/s) <em>j</em>
The ground speed is the magnitude of this vector:
||<em>g</em>|| = √[ (-55.0 m/s)² + (325 m/s)² ] ≈ 330. m/s
which is faster than the air speed, which is ||<em>a</em>|| = 325 m/s.
Answer:
"13.48 Kwhr" is the right solution.
Explanation:
The given values are:
Average rate of heat energy,
= 0.063 W/m²
Diameter,
= 8m
Efficiency of conversion,
= 50%
Now,
The area of hotspot will be:
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
Total heat generation rate will be:
⇒ 


hence,
The electricity generation capacity will be:
⇒ 
On substituting the values, we get
⇒ 
⇒ 
On converting into Kwhr, we get
⇒ 
Answer:increasing any of them, either mass or speed by 1unit will cause an increase in energy,
Explanation:
By increasing any of them, either mass or speed will cause an increase in energy.
Because kinetic energy is proportional to mass and also directly proportional to velocity
Answer:
Distance will be 
Explanation:
We have given that Buffalo has a latitude of 42.9°N
And Raleigh has a latitude of 35.8°N
Radius of the earth = 3960 miles
We have to calculate the distance between given two cities
Difference in their latitudes = 
Now changing the angle in radian = 
So distance will be 