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ivolga24 [154]
3 years ago
5

2. What is the power rating of an engine capable of lifting a 100 kg object 5 m vertically

Physics
1 answer:
Leya [2.2K]3 years ago
7 0
Work=f.d
Work=100*50 = 500
Power = work/time = 500/4
=125 watt
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Hi please may someone help me especially on the sketch part.
vaieri [72.5K]

Ignoring the air resistance it will take about 3 seconds for the object to reach the ground.We know that the acceleration due to gravity is 10m/s2.

We also know that the final velocity is 30 m/s while the initial velocity is 0 m/s

we can use the formulae for acceleration to calculate the time taken/

(final - initial velocity)/timetaken=10

(30-0)/timetaken=10

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Calculate the acceleration of a 270000-kg jumbo jet just before takeoff when the thrust on the aircraft is 160000 N .
Radda [10]

Answer:

<h3>The answer is 0.59 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

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We have the final answer as

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Hope this helps you

7 0
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