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3 years ago

2. What is the power rating of an engine capable of lifting a 100 kg object 5 m vertically

Physics

1 answer:

Leya [2.2K]3 years ago

7 0

Work=f.d
Work=100*50 = 500
Power = work/time = 500/4
=125 watt

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tankabanditka [31]

Answer: 1) t=0.5 s; S=6.225 m and v=14.9 m/s

2) t=1 s; S=14.9 m and v=19.8 m/s

3) t=1.5 s; S=26.05 m and v=24.7 m/s

Explanation:

The displacement $S$ is given by

$S=ut+\frac{1}{2} at^{2}$

and final velocity $v$ is given by

$v=u+at$

where $u$ is the initial velocity

$a$ is acceleration

$t$ is time taken

Case 1: when time is 0.5 s

The displacement is

$S=ut+\frac{1}{2} at^{2}\\S=10\times 0.5 +\frac{1}{2}\times 9.8\times 0.5^{2}\\\\S=6.225 m$

the velocity is

$v=u+at\\v=10+9.8\times 0.5\\v=14.9 m/s$

Case 2: when t=1 sec

The displacement is

$S=ut+\frac{1}{2} at^{2}\\S=10\times 1 +\frac{1}{2}\times 9.8\times 1^{2}\\\\S=14.9 m$

the velocity is

$v=u+at\\v=10+9.8\times 1\\v=19.8 m/s$

Case 3: t=1.5 s

The displacement is

$S=ut+\frac{1}{2} at^{2}\\S=10\times 1.5 +\frac{1}{2}\times 9.8\times 1.5^{2}\\\\S=26.05 m$

the velocity is

$v=u+at\\v=10+9.8\times 1.5\\v=24.7 m/s$

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3 years ago

In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the

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We will determine the wavelength through the relationship given by the distance between slits, this relationship is given under the function

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Here,

m = Number of order bright fringe

$\lambda$ = Wavelength

d = Distance between slits

Both distance are the same, then

$y_1 = y_2$

$\frac{m_1\lambda_1 r}{d} = \frac{m_2\lambda_2 r}{d}$

$\frac{m_1\lambda_1}{m_2\lambda_2} =1$

Rearranging to find the second wavelength

$m_1 \lambda_1 = m_2 \lambda _2$

$\lambda_2 = \frac{m_1\lambda_1}{m_2}$

$\lambda_2 = \frac{7(629)}{8}$

$\lambda_2 = 550.3nm$

Therefore the wavelength of the light coming from the second monochromatic light source is 550.3nm

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A 2300 Kg car accelerates from rest to 6.00 m/s in 12.00 seconds. What is the net force acting in the car?

pav-90 [236]

F=ma
a=(v2-v1)/(t2-t1)
a=(6-0)/(12-0)
a=6/12
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f=2300kg*.5m/s^2
f=1150N
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Answer:

we know,

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Answer:

I wish I knew

Explanation:

Ummm

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