3 years ago

2. What is the power rating of an engine capable of lifting a 100 kg object 5 m vertically

Physics

1 answer:

Leya [2.2K]3 years ago

7 0

Work=f.d
Work=100*50 = 500
Power = work/time = 500/4
=125 watt

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Answer:

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v1 = 9*10^4 m/s

From conservation of energy

K1 +U1 = K2 +U2

0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2

0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2

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0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))

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Answer:

different value to l if n=5 are 0,1,2,3,4

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3 years ago

What is solar energy?

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You throw a bouncy rubber ball and a wet lump of clay, both of mass m, at a wall. Both strike the wall at speed v, but while the

lana [24]

Answer:

<em>The fifth option is the correct answer: mv; 2 mv</em>

Explanation:

<u>Change of Momentum</u>

Assume an object has a momentum p1 and after some interaction it now has a momentum p2, the change of momentum is

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The momentum is computed as

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$p_1=mv$

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$\Delta p=0-mv=-mv$

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$p_2=-mv$

The change of momentum is

$\Delta p=-mv-mv=-2mv$

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The fifth option is the correct answer: mv; 2 mv

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