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kogti [31]
2 years ago
12

Five groups of four vectors are shown below. All magnitudes of individual vectors are equal. Please rank the groups based on the

magnitude of the resultant vectors if the four vectors in each group were added together. Rank the groups of vectors from the greatest resultant magnitude to the smallest resultant magnitude.
Rank the groups of vectors from the greatest resultant magnitude to the smallest resultant magnitude.

Physics
1 answer:
valkas [14]2 years ago
5 0

With the addition of vectors we can find that the correct answer is:

   C)   Q> P > R =  S > T

The addition of vectors must be done taking into account that they have modulus and direction. The analytical method is one of the easiest methods, the method to do it is:

  • Set a Cartesian coordinate system
  • Decompose vectors into their components in a Cartesian system
  • Perform the algebraic sums on each axis
  • Find the resultant vector using the Pythagoras' Theorem to find the modulus and trigonometry to find the direction.

In this exercise indicate that the modulus of all vectors is the same, suppose that the value of the modulus is A.

We fix a Cartesian coordinate system with the horizontal x axis and the vertical y axis, we can see that we do not need to perform any decomposition, so we perform the algebraic sums

Diagram P

x-axis

         x = 2A

y-axis  

         y = 2A

The modulus of the resulting vector can be found with the Pythagorean Theorem

          P = \sqrt{x^2+y^2}

          P = \sqrt{4A^2 +4A^2 }= \sqrt{8}  \  A

          P = 2 √2  A

         

Diagram Q

x-axis

        x = 3A

y-axis  

        y = A

Resulting

       Q = \sqrt{x^2+y^2}

       Q =\sqrt{9A^2 + A^2 }  

       Q = \sqrt{10} \ A

       

Diagram R

x- axis

       x = 0

y-axis

        y = 2 A

Resulting

       R =\sqrt{4A^2 + 0}  

       R = \sqrt{4} \ A

Diagram S

x-axis

       x = 2 A

y-axis

        y = 0

 

Resulting

       S = 2A

Diagram T

x- axis

      x = 0

y-axis  

      y = 0

Resultant T = 0

We order the diagram from highest to lowest

    Q> P> R = S> T

When reviewing the different answers, the correct one is:

   C.  Q> P> R = S> T

Learn more about adding vectors here:

brainly.com/question/14748235

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When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 12.0 cm. The mass is now displ
Ray Of Light [21]

Answer:

period of oscillations is 0.695 second

Explanation:

given data

mass m = 0.350 kg

spring stretches x = 12 cm = 0.12 m

to find out

period of oscillations

solution

we know here that force

force = k × x   .........1

so force = mg =  0.35 (9.8)  = 3.43 N

3.43 = k × 0.12

k = 28.58 N/m

so period of oscillations is

period of oscillations = 2π × \sqrt{\frac{m}{k} }   ................2

put here value

period of oscillations = 2π × \sqrt{\frac{0.35}{28.58} }  

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4 0
3 years ago
A 0.15 g honeybee acquires a charge of 22 pC while flying. The electric field near the surface of the earth is typically 100 N/C
Rus_ich [418]

Answer:

1.50\ *10^{-6} }

Explanation:

Given

e=100 N/C

M=0.15 g

q=\ 22\  pC\\=\ 22\ *10^{-2}

The  ratio of the electric force on the bee to the bee's weight can be determined by the following formula

\frac{fe}{M*9.81}

\frac{22*10^{-12\ *\ 100} }{0.15*\ 10^{-3} *\ 9.81}

=\ 1.50\ *10^{-6}

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4 years ago
A roller of radius 12.5 cm turns at 14 revolutions per second. What is the linear velocity of the roller in meters per second?
Firdavs [7]

12.5 times 14 and convert to meters its 1.75 meters per second

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3 years ago
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