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2 years ago

Complete the passage about the properties of ionic compounds.

Chemistry

1 answer:

WITCHER [35]2 years ago

3 0

Answer:

Following are the solution to the given question:

Explanation:

Due to the strong attachment among ions, it's indeed hard to break the covalent compounds in a combination. The ionic compounds, as they have a great melting point, become solid at room temperature, and may we say that the stronger between both the ions, as it is on a high point of fusion, is quite desirable.

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Which idea did linnaeus contribute to the theory of evolution

MissTica

Answer:

Binomial Naming System

Explanation:

He was the first to use the system, he used it frequently enough for the system to be accepted and used more often by scientists. He believed that species were unable to be changed.

6 0

3 years ago

A compound has an empirical formula of CH2 and a molar mass of 56 g. What is its molecular formula?

kipiarov [429]

Answer:

C4H8

Explanation:

First find the molar mass of CH2;

2(1.01) + 1(12.01) = 14.03g

Now divide the molar mass of the compound by the molar mass of CH2;

56g/14.03g = 3.9914 Round to nearest whole number = 4

Multiply CH2 by 4 to get the molecular formula;

CH2* 4 = C4H8

4 0

3 years ago

PLEASE ANSWER

lisov135 [29]

Answer:

Explanation:

8 0

3 years ago

Write a balanced equation for the following reaction:

tiny-mole [99]

Answer:

3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄

The coefficients are 3, 1, 3, 1

Explanation:

From the question given above, the following data were:

Silver chloride reacts with sodium phosphate to yield sodium chloride and silver phosphate. This can be written as follow:

AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄

The above equation can be balanced as follow:

AgCl + Na₃PO₄ —> NaCl + Ag₃PO₄

There are 3 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 3 in front of NaCl as shown below:

AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄

There are 3 atoms of Cl on the right side and 1 atom on the left. It can be balance by putting 3 in front of AgCl as shown below:

3AgCl + Na₃PO₄ —> 3NaCl + Ag₃PO₄

Thus, the equation is balanced.

The coefficients are 3, 1, 3, 1

6 0

3 years ago

What mass, in grams, of CO2 and H2O is formed from 2.55 mol of propane?

oksian1 [2.3K]

Answer:

336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.

Explanation:

In this case, the balanced reaction is:

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactant and product participate in the reaction:

C₃H₈: 1 mole
O₂: 5 moles
CO₂: 3 moles
H₂O: 4 moles

Being the molar mass of each compound:

C₃H₈: 44 g/mole
O₂: 16 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

Then, by stoichiometry, the following quantities of mass participate in the reaction:

C₃H₈: 1 mole* 44 g/mole= 44 grams
O₂: 5 moles* 16 g/mole= 80 grams
CO₂: 3 moles* 44 g/mole= 132 grams
H₂O: 4 moles* 18 g/mole= 72 grams

So you can apply the following rules of three:

If by stoichiometry 1 mole of C₃H₈ forms 132 grams of CO₂, 2.55 moles of C₃H₈ how much mass of CO₂ will it form?

$mass of CO_{2} =\frac{2.55 moles of C_{3} H_{8}*132 gramsof CO_{2} }{ 1 mole of C_{3} H_{8}}$

mass of CO₂= 336.6 grams

If by stoichiometry 1 mole of C₃H₈ forms 72 grams of H₂O, 2.55 moles of C₃H₈ how much mass of H₂O will it form?

$mass of H_{2}O =\frac{2.55 moles of C_{3} H_{8}*72 gramsof H_{2}O }{ 1 mole of C_{3} H_{8}}$

mass of H₂O= 183.6 grams

336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.

3 0

3 years ago