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Andrew [12]
2 years ago
11

Complete the passage about the properties of ionic compounds.

Chemistry
1 answer:
WITCHER [35]2 years ago
3 0

Answer:

Following are the solution to the given question:

Explanation:

Due to the strong attachment among ions, it's indeed hard to break the covalent compounds in a combination. The ionic compounds, as they have a great melting point, become solid at room temperature, and may we say that the stronger between both the ions, as it is on a high point of fusion, is quite desirable.

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Gas law problem: A gas has a volume of 800 mL at -25℃ and 600 kPa. What would the volume of the gas be at 227℃ and 1000 kPa?
Sati [7]
<h3><u>Answer;</u></h3>

= 930.23 mL

<h3><u>Explanation</u>;</h3>

Using the combined gas law;

P1V1/T1 = P2V2/T2

Where; P1 = 600 kPa, V1 = 800 mL, and T1 = -25 +273 = 258 K, and

V2= ?, P2 = 1000 kPa, and T2 = 227 +273 = 500 K

Thus;

V2 = P1V1T2/T1P2

     = (600 ×800 ×500) / (258 × 1000)

     = 930.23 mL

5 0
3 years ago
What effect might a hydroxyl group on a benzene ring of the reactant have on this reaction?
Zigmanuir [339]

Hey there!:

The hydroxyl groups act to neutralize the sodium borohydride which reduces yield.


Hope that helps!

6 0
3 years ago
The graph above shows how the price of cell phones varies with the demand quantity. The equilibrium price for cell phones is ___
elena-s [515]

It's this one $100, 5,000

8 0
3 years ago
Read 2 more answers
Look at this balanced chemical reaction: N2 + 3H2 2NH3
stepladder [879]

Answer: A mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.

Explanation:

Given: Volume = 450 L

Temperature = 450 K

Pressure = 300 atm

Using ideal gas equation, moles of nitrogen are calculated as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = tempertaure

Substitute values into the above formula as follows.

PV = nRT\\300 atm \times 450 L = n \times 0.0821 L atm/mol K \times 450 K\\n = \frac{135000}{36.945}\\= 3654.08 mol

According to the given equation, 1 mole of nitrogen forms 2 moles of ammonia. So, moles of ammonia formed by 3654.08 moles of nitrogen is as follows.

2 \times 3654.08 mol\\= 7308.16 mol

As moles is the mass of substance divided by its molar mass. So, mass of ammonia (molar mass = 17.03 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\7308.16 = \frac{mass}{17.03 g/mol}\\mass = 124457.96 g

Thus, we can conclude that a mass of 124457.96 g ammonia is produced by reacting a 450 L sample of nitrogen gas at a temperature of 450 K and a pressure of 300 atm.

8 0
3 years ago
What is the solubility of ethylene (in units of grams per liter) in water at 25 °C, when the C2H4 gas over the solution has a pa
vredina [299]

<u>Answer:</u> The solubility of ethylene gas in water is 9.16\times 10^{-2}g/L

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{C_2H_4}=K_H\times p_{C_2H_4}

where,

K_H = Henry's constant = 4.78\times 10^{-3}mol/L.atm

C_{C_2H_4} = molar solubility of ethylene gas = ?

p_{C_2H_4} = partial pressure of ethylene gas = 0.684 atm

Putting values in above equation, we get:

C_{C_2H_4}=4.78\times 10^{-3}mol/L.atm\times 0.684atm\\\\C_{C_2H_4}=3.27\times 10^{-3}mol/L

Converting this into grams per liter, by multiplying with the molar mass of ethylene:

Molar mass of ethylene gas = 28 g/mol

So, C_{C_2H_6}=3.27\times 10^{-3}mol/L\times 28g/mol=9.16\times 10^{-2}g/L

Hence, the solubility of ethylene gas in water is 9.16\times 10^{-2}g/L

6 0
3 years ago
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