<span>Molecular compounds, which are represented by molecules, are usually made of non-metals only (or of metalloids and non-metals). Ionic compounds, which are represented by formula units, are made of metals and non-metals.
More detail if you're interested: Molecules and formula units are the representative particles for molecular and ionic compounds, respectively. By that I mean, one unit of a molecular compound is a molecule...a bundle of atoms covalently bonded that exists separately from all the other molecules. One unit of an ionic compound is a formula unit. A formula unit is a representation of the compound's formula. For example, the formula unit of NaCl is one Na^+1 ion and one Cl^-1 ion. The formula unit of AlCl3 is one Al^+3 ion and three Cl^-1 ions. Ionic compounds don't have separate bundles of atoms like molecular compounds do, so the formula unit is just the smallest number of ions that it takes to represent the formula. </span>
Answer:
The correct answer is <em>d. The nucleoside triphosphates have the sugar deoxyribose; ATP has the sugar ribose.</em>
Explanation:
The nucleoside triphosphates are components of DNA (deoxyribonucleic acid) so they are composed by a nitrogenous base (adenine, guanine, thymine or cytosine) and a deoxyribose sugar. In contraposition, ATP (adenosine triphosphate) is composed by the nitrogenous base adenine and a ribose sugar along with three phosphates groups. Unlike ribose, deoxyribose is a 5-carbon sugar which lack of an oxygen atom in C2 position.
Answer : The heat of combustion of n-propanol is 0.554 kJ/mol
Explanation :
First we have to calculate the moles of n-propanol.
Molar mass of n-propanol = 60.09 g/mole
Now we have to calculate the heat of combustion of n-propanol.
As, 0.0166 mole of n-propanol liberated heat of combustion = -33.4 kJ
So, 1 mole of n-propanol liberated heat of combustion = 0.0166 × (-33.4 kJ)
= 0.554 kJ/mol
Therefore, the heat of combustion of n-propanol is 0.554 kJ/mol
Answer:
by repeating the experiment several times
Explanation:
A scientist conducted one trial of an experiment and got unexpected results. Therefore, he should repeat his experiment and see if he is getting the same result again or not. If the result is again the same and does not matches his expectations then he should discuss the results with other scientist. If the result is different, then he should check for the cause of error.
