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3 years ago

ADvantage of friction

Physics

1 answer:

kondor19780726 [428]3 years ago

7 0

Answer:

1. Friction enables us to walk freely.

2. It helps to support ladder against wall.

3. It becomes possible to transfer one form of energy to another.

4. Objects can be piled up without slipping.

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Bailey wants to find out which frozen solid melts the fastest: soda, ice, or orange juice. She pours each of the three liquids i

777dan777 [17]

Answer:

its 45 over 6

Explanation:the answer is in the question

8 0

3 years ago

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How much heat is needed to raise the temperature of 1 kg of iron from 25 degree to 30 degrees?

stiv31 [10]

Answer:300 joules

Explanation:The formula for specific heat is:

, where:

is the energy needed in joules,

is the mass in kilograms,

is the specific heat,

is the change in temperature, Celsius of Kelvin doesn't matter.

Here,

0.125

480

J/kg

∘

, and inputting:

0.125

⋅

480

⋅

300

of energy is needed.

4 0

4 years ago

What type of energy is kinetic energy

Svetradugi [14.3K]

Kinetic energy is energy in motion, and it is a type of energy.

3 0

3 years ago

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If x =(20-4t^2) find average velocity between t=0and t=2sec

lapo4ka [179]

Answer:

The average velocity is 8 unit per sec

Explanation:

Given as :

The Distance x = 20 - 4t² unit

Change in time Δt = ( 2 - 0 ) s = 2 s

Let the velocity = V unit/s

∴ V = $\frac{\partial (20 - 4t^{2})}{\partial x}$

Or, V = - 8t unit/s

Now velocity at t = 0

V1 = - 8 × 0 = 0 unit/s

And velocity at t = 2 sec

V2 = - 8 × 2 = - 16

So, Average velocity = $\frac{v2 - v1}{2}$ = $\frac{- 16 - 0}{2}$ = -8

Or, $\begin{vmatrix}V\end{vmatrix}$ = 8 unit/sec

Hence The average velocity is 8 unit per sec Answer

6 0

3 years ago

A satellite, orbiting the earth at the equator at an altitude of 400 km, has an antenna that can be modeled as a 1.76-m-long rod

ivann1987 [24]

Answer:

The inducerd emf is 1.08 V

Solution:

As per the question:

Altitude of the satellite, H = 400 km

Length of the antenna, l = 1.76 m

Magnetic field, B = $8.0\times 10^{- 5}\ T$

Now,

When a conducting rod moves in a uniform magnetic field linearly with velocity, v, then the potential difference due to its motion is given by:

$e = - l(vec{v}\times \vec{B})$

Here, velocity v is perpendicular to the rod

Thus

e = lvB (1)

For the orbital velocity of the satellite at an altitude, H:

$v = \sqrt{\frac{Gm_{E}}{R_{E}} + H}$

where

G = Gravitational constant

$m_{e} = 5.972\times 10^{24}\ kg$ = mass of earth

$R_{E} = 6371\ km$ = radius of earth

$v = \sqrt{\frac{6.67\times 10^{- 11}\times 5.972\times 10^{24}}{6371\times 1000 + 400\times 1000} = 7670.018\ m/s$

Using this value value in eqn (1):

$e = 1.76\times 7670.018\times 8.0\times 10^{- 5} = 1.08\ V$

5 0

3 years ago