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3 years ago

The magnetic field 0.100 m from a

Physics

1 answer:

Aneli [31]3 years ago

4 0

Answer:

Your answer is given below:

Explanation:

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The metal with the highest melting temperature is tungsten which melts at around 3400 K. What is the wavelength of the peak of t

alekssr [168]

Explanation:

It is given that, the metal with the highest melting temperature is tungsten which melts at around 3400 K, T = 3400 K

We need to find the wavelength of the peak of the black body distribution for this temperature. It can be calculated using Wein's displacement law as :

$\lambda\times T=k$

k is the constant, $k=2.89\times 10^{-3}\ m.k$

$\lambda=\dfrac{k}{T}$

$\lambda=\dfrac{2.89\times 10^{-3}\ m.k}{3400\ k}$

$\lambda=8.5\times 10^{-7}\ m$

$\lambda=850\ nm$

The wavelength of infrared is from 700 nm to 1 mm. So, the lies in infrared region of the spectrum. Hence, this is the required solution.

7 0

4 years ago

A car was driving at a speed of 10 m/s. In 3 seconds, it accelerated to a speed of 50 m/s. Calculate the car's acceleration.

Thepotemich [5.8K]

Answer:

$\boxed {\boxed {\sf 13.3 \ m/s^2}}$

Explanation:

Acceleration is the rate of change of velocity with respect to time. It is the change in velocity over the change in time, and it is calculated using the following formula.

$a= \frac{ v_f-v_i}{t}$

The car starts at a speed of 10 meters per second, then it accelerates to a speed of 50 meters per second. It achieves this acceleration in 3 seconds.

$v_f$ = 50 m/s
$v_i$ = 10 m/s
t= 3 s

Substitute the values into the formula.

$a= \frac{50 \ m/s - 10 \ m/s}{3 \ s}$

Solve the numerator.

50 m/s -10 m/s= 40 m/s

$a= \frac{40 \ m/s}{3 \ s}$

Divide.

$a= 13.3333333 \ m/s/s$

$a \approx 13.3 \ m/s^2$

The car's acceleration is approximately 13.3 meters per second squared.

6 0

2 years ago

A wind turbine is rotating counterclockwise at 0.626 rev/s and slows to a stop in 12.9 s. Its blades are 17.9 m in length. What

iogann1982 [59]

Answer:

276.5 m/s^2

Explanation:

The initial angular velocity of the turbine is

$\omega=0.626 rev/s \cdot 2\pi rad/rev =3.93 rad/s$

The length of the blade is

r = 17.9 m

So the centripetal acceleration is given by

$a=\omega^2 r$

At the instant t = 0,

$\omega=3.93 rad/s$

So the centripetal acceleration of the tip of the blades is

$a=(3.93 rad/s)^2 (17.9 m)=276.5 m/s^2$

5 0

3 years ago

A car has an engine which delivers a constant power. It accelerates from rest at time t = 0, and at t = t0 its acceleration is a

olga2289 [7]

Here is the answer of the given problem above.
Use this formula: P = FV = ma*at = ma^2 t
Substitute the values, and therefore, we got m(a0)^2t = m(x)^2 (2t)
then, solve for x which is the acceleration at 2t.
The answer would be a0/sqrt(2).
Hope this answers your question. Thanks for posting.

7 0

4 years ago

Alguien que sepa de electromecánica porfavor

kkurt [141]

LAPA HDIDOSHSUWJWVWIHDHDOSSHSVWIME

8 0

3 years ago