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arsen [322]
2 years ago
5

Assignment Directions:

Chemistry
1 answer:
Alja [10]2 years ago
8 0

Answer:

For this assignment, I have picked three famous soccer players from around the world. I will go over their Birth, work ethic, and downfalls. I guess that most soccer players' downfalls are going to be their injuries.

The first soccer player I found was Ricardo Kakà. Ricardo Kakà was born to Simone dos Santos, his mother, and Bosco Izecson Pereira Leite, his father, on April 22, 1982. His work ethic mostly consists of "doing it". One of Ricardo Kakà's greatest downfalls is his injuries.

The second player I found was Cristiano Ronaldo. Cristiano Ronaldo was born to Maria Dolores dos Santos and José Dinis Aveiro. He was introduced to soccer by his dad because worked at a soccer field. Cristiano Ronaldo's work ethic consisted of something that Ricardo Kakà had as well. "Get it done". Cristiano Ronaldo's downfall was that his father drank too much.

I was not surprised to see that, but I thought it was going to be injuries as well.

The final player that I picked is Luis Suárez. Luis Suárez was born to Sandra Diaz and Rodolfo Suárez. He joined his local youth team that played soccer and he loved it. His work ethic is the same as the last soccer players. "Do it." His major downfall was that he was a bad-tempered teen and he got mad at stuff. That didn't help him when his parents divorced.

Overall all of the soccer players are different and very important. They have all gone through different situations and have gotten through them through soccer.

Explanation:

This is not 300 words, it is 244. You can it. Make sure to change it so it sounds like you wrote it.  

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Alborosie

Explanation:

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Answer:

The final volume of NaOH solution is 30ml

Explanation:

We all know that

              V1S1 = V2S2

             or V1= V2S2÷S1

             or  V1= V2×S2×1/S1

             or   V1=100×0.15×1/0.50

                    V1= 30

∴30 ml NaOH solution is required to prepare 0.15 M from 100ml 0.50 M NaOH solution.

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How many particles are in a 151 g sample of Li2O?
neonofarm [45]

Answer:

3.052 × 10^24 particles

Explanation:

To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)

The mass of Li2O given in this question is as follows: 151grams.

To convert this mass value to moles, we use;

moles = mass/molar mass

Molar mass of Li2O = 6.9(2) + 16

= 13.8 + 16

= 29.8g/mol

Mole = 151/29.8g

mole = 5.07moles

number of particles (nA) of Li2O = 5.07 × 6.02 × 10^23

= 30.52 × 10^23

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4 0
3 years ago
The empirical formula of an organic compound is C2H4O. The molecular mass of the compound is 176g/mol.
Brrunno [24]

Answer:

The molecular formula of the compound is C_{8}H_{16}O_{4}. The molecular formula is obtained by the following expression shown below

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Explanation:

Given molecular mass of the compound is 176 g/mol

Given empirical formula is  C_{2}H_{4}O

Atomic mass of carbon, hydrogen and oxygen are 12 u , 1 u and 16 u respectively.

Empirical formula mass of the compound = \left ( 2\times12+4+16 \right ) \textrm{ u} = 44 \textrm{ g/mol}

n = \displaystyle \frac{\textrm{Molecular formula mass}}{\textrm{Empirical formula mass}} \\n = \displaystyle \frac{176}{44} = 4

\textrm{Molecular formula }= n\times \textrm{Empirical formula}

Molecular formula = 4 \times C_{2}H_{4}O

Molecular formula is C_{8}H_{16}O_{4}

6 0
3 years ago
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