I don’t know how , what class is it for?
<span>You will use an ideal gas equation here. Let us denote 'x' as the unknown sample of zinc if another 1 ml of it is added to make a total of 476mL gas. The ideal gas equation is PV = nRT. Assume atmospheric conditions and then substitute everything to the equation.
(1atm)(0.476L) = (1.85 + x)(0.08206 L-atm/mol-K)(20.5+273K)
x = 1.83 g of zinc</span>
Answer:
c 3 mol of Ba(OH)₂ and 1 mol of Ba₃N₂ should be interchanged
Explanation:
Ba₃N₂ + 6H₂O → 3Ba(OH)₂ + 2NH₃
n/mol: 9.2

They want to find moles of Ba₃N₂, so that should be in the numerator of the conversion factor,
Moles of Ba(OH)₂ should be in the denominator to cancel the units in 9.2 mol Ba(OH)₂,
The heat is measured with degree Celsius and degree Fahrenheit. The heat capacity depends on both it's mass and it's chemical composition.