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Viktor [21]
3 years ago
13

How does the gravitational pull of different objects in space affect other objects in space?

Physics
1 answer:
Vinvika [58]3 years ago
3 0

Answer:

Every object in space exerts a gravitational pull on every other.

Explanation:

gravity influences the paths taken by everything traveling through space. It is the glue that holds together entire galaxies. It keeps planets in orbit. It can also cause life-destroying asteroids to crash into planets.

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An apparatus like the one Cavendish used to find G has large lead balls that are 5.2 kg in mass and small ones that are 0.046 kg.
Ber [7]

Answer:

The magnitude of gravitational force between two masses is 4.91\times 10^{-9}\ N.

Explanation:

Given that,

Mass of first lead ball, m_1=5.2\ kg

Mass of the other lead ball, m_2=0.046\ kg

The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m

We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :

F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67259\times 10^{-11}\times \dfrac{5.2\times 0.046}{(0.057)^2}\\\\F=4.91\times 10^{-9}\ N

So, the magnitude of gravitational force between two masses is 4.91\times 10^{-9}\ N. Hence, this is the required solution.

5 0
3 years ago
A car moves in a straight line at 22.0 m/s for 10.0miles, then at 30.0 m/s for another 10.0miles. Calculate the car’s average sp
maw [93]

Answer: 25.38 m/s

Explanation:

We have a straight line where the car travels a total distance D, which is divided into two segments d=10 miles:

D=d+d=2d (1)

Where d=10mi \frac{1609.34 m}{1 mi}=16093.4 m

On the other hand, we know speed is defined as:

S=\frac{d}{t} (2)

Where t is the time, which can be isolated from (2):

t=\frac{d}{S} (3)

Now, for the first segment d=16093.4 m the car has a speed S_{1}=22m/s, using equation (3):

t_{1}=\frac{d}{S_{1}} (4)

t_{1}=\frac{16093.4 m}{22m/s} (5)

t_{1}=731.518 s (6) This is the time it takes to travel the first segment

For the second segment d=16093.4 m the car has a speed S_{1}=30m/s,  hence:

t_{2}=\frac{d}{S_{2}} (7)

t_{2}=\frac{16093.4 m}{30m/s} (8)

t_{2}=536.44 s (9) This is the time it takes to travel the secons segment

Having these values we can calculate the car's average speed S_{ave}:

S_{ave}=\frac{d + d}{t_{1} + t_{2}}=\frac{2d}{t_{1} + t_{2}} (10)

S_{ave}=\frac{2(16093.4 m)}{731.518 s +536.44 s} (11)

Finally:

S_{ave}=25.38 m/s

3 0
4 years ago
1. A boat initially moving at 10 m/s accelerates at 2 m/s2 for 10 s. What is the velocity of the boat after 10 seconds?​
DIA [1.3K]

Answer:

5 m/s is the answer so yeah

5 0
3 years ago
If Karen rode her bicycle 5 km to school in 30 minutes, what was her average speed? Give your answers in km/h.
Doss [256]

Answer:

10 km/h

Explanation:

Before calculating the average speed, we need to convert the time taken for the trip from minutes to hours. Since 1 hour cointains 60 minutes, we have:

1 h: 60 min = t : 30 min\\t=\frac{1 h \cdot 30 min}{60 min}=0.5 h

Karen's average speed is given by:

v=\frac{d}{t}

where

d = 5 km is the distance covered

t = 0.5 h is the time taken for the trip

Substituting into the equation, we find

v=\frac{5 km}{0.5 h}=10 km/h

5 0
4 years ago
Seatbelts are necessary to prevent your body from flying out of a vehicle during a crash. why does your body not stop with the c
Svetlanka [38]
Because you are separate from the car.
6 0
4 years ago
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