Answer:
C - higher volume
Explanation:
The pitch or frequency of sound that an object can produce depends upon its size and configuration . The shape of hand of all are same so the frequency of sound produced by hands of all will be almost same . Hence frequency of sound produced by the hands of Anand and Kumar would have been almost the same .
But the intensity of sound produced by them would have been different . Intensity represents energy a sound carries . Hard hitting clap will produce sound of higher intensity . Intensity of sound is also called high volume sound . So Kumar's clap will carry greater energy and hence greater volume of sound .
Hello, for this applicate formula:
Vf² = Vo² + 2gh
Data:
Vf = Final Velocity = ¿?
Vo = Initial veloctiy = 0 m/s
g = Gravity = 9,81 m/s²
h = Height = 5 m
Replacing according our data:
Vf² = 0 m/s² + 2(9,81 m/s²)(5 m)
Vf² = 98,1 m²/s²
Vf = √98,1 m²/s²
Vf = 9,9 m/s
The final velocity will be <u>9,9 meters per second.</u>
Answer: light waves travel further than sound waves
Explanation:
Answer:
480
Explanation:
resistance equals to potential difference divide by electric current
120÷0.25
=480
Answer:
μ = 0.66, therefore if it compiesy with the regulations
Explanation:
Let's solve this exercise in part, let's start by finding with kinematics the acceleration of man
y = v₀ t + ½ a t²
as it starts from rest the initial velocity is zero
y = ½ a t²
a =
a =\frac{2 \ 4.38}{1.21^2}
a = 6.46 m / s²
Now let's use Newton's second law,
Axis y
N- W = 0
N = W
N = m g
X axis
on this axis the man exerts a backward force and by the law of action and reaction the floor exerts a forward force of the same magnitude, this forward force is the friction force.
fr = m a
the friction force has an expression
fr = my N
let's substitute
μ mg = m a
μ = a / g
let's calculate
μ = 6.46 / 9.8
μ = 0.66
therefore if you comply with the regulations