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Len [333]
3 years ago
10

I got a new kitten and I dont know how to train them to use a leash. Can anyone help?

Physics
1 answer:
Lerok [7]3 years ago
7 0
Put the leash on and have like treats with u and they will follow u that’s how I trained my cat lol
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What kind of research in teaching of physical science can be done???​
11Alexandr11 [23.1K]

Answer:

Physical sciences are those academic disciplines that aim to uncover the underlying laws of nature - often written in the language of mathematics. It is a collective term for areas of study including astronomy, chemistry, materials science and physics.

Explanation:

3 0
2 years ago
The melting point of pure water is _____.<br><br> 32°C<br><br> 100°C<br><br> 0°C<br><br> 212°C
BabaBlast [244]

Answer:

0°C and 32°F

Explanation:

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3 0
2 years ago
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The planting of trees is determined to soil because it drains the soil of nutrients True or false
frutty [35]
True


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3 0
3 years ago
Some of the energy the car gained as it was pulled was lost because of heat from friction. The rest of the energy was transforme
Lisa [10]

Answer:

454,320 joules

Explanation:

The work done on an object is equal to its change in kinetic energy: Change in KE = F × d.

Plug the values for F and d into the formula and solve:

Change in KE = 2,524 × 180

= 454,320 joules

The roller coaster gains 454,320 joules of energy from the work done on it by the chain.

7 0
3 years ago
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A body of mass 2 kg is moving in the positive X-Direction with a speed of 4 m/s collides head on with an another body of mass 3
Inga [223]
m_1=2 \\ m_2=3 \\ v_1=4 \\ v_2=1 \\ v\text{ =speed after collision (to be determined)}.

The momentul of the system preserves:

m_1v_1-m_2v_2=(m_1+m_2)v \ \ \ \ \ \Rightarrow \ \ \ \ \ v=\dfrac{m_1v_1-m_2v_2}{m_1+m_2}.

Ok, we found the speed after the collision.
Now, because the impact is plastic, it produces heat, sound energy and who knows what other forms of energy. We denote all this wasted energy with E.

Now, we write the energy conservation law:

\dfrac{m_1v_1^2}{2}+\dfrac{m_2v^2_2}{2}=\dfrac{(m_1+m_2)v^2}{2}+E

From the above equation, you find E,  and then conclude that the sound energy can certainly not be greater than this.
8 0
2 years ago
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