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NeTakaya
3 years ago
7

An object is placed 50cm in front of a concave mirror of radius 60cm. How far from the mirror is the image?

Physics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:To explian the exact calculation of this pruduct we must not try!

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63 J of heat are added to a closed system. The initial energy of the system is 58J, and the final internal energy is 93J. How mu
Nesterboy [21]

ΔU = Q + W  

  • heat in, Q +  
  • heat out, Q -  
  • does work , W -  
  • work in, W +

93-58 = 63 + W

35 = 63 + W

W = - 28 J (does work/being done by system)

7 0
2 years ago
Physics pls help
seropon [69]
First one is correct
3 0
3 years ago
Read 2 more answers
A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 6.55x10-2 kg/s. The density of the gasoline is 740
klasskru [66]

Answer:

speed = 3.95 m/s

Explanation:

area = π x radius^2

area = π x (2.67 x 10^-3)^2

volume flow rate = area x speed

volume / time = area x speed

density = mass / volume

volume = mass / density

<u>mass / (density x time) = area *speed</u>

mass flow rate = mass / time

<u>mass flow rate / density = area x speed</u>

6.55 x 10^-2 / 740 = pi * (2.67 x 10^-3)^2 * speed

speed =8.8514 x 10-5 /2.2396 x 10-5 m/s

speed = 3.95 m/s

6 0
3 years ago
What makes a clinical thermometer suitable for measuring small changes in body temperature? *
Nana76 [90]

Answer: Because of the fine bore of the tube.

Explanation:

Temperature is the degree of hotness and coldness. And thermometer is the instrument use to measure temperature.

The two most common types of themometric fluids for thermometer are alcohol and mercury.

What makes a clinical thermometer suitable for measuring small changes in body temperature is because of the fine bore of the tube which makes it possible for small temperature changes to cause large changes in the length of mercury columns, making the thermometer very sensitive to temperature changes.

The most prominent feature of the thermometer is the kink or constriction of bore near the bulb.

4 0
3 years ago
How high would a projectile go if it was launched from ground level with an initial speed of 26 m/s at an angle of 30 degrees ab
tigry1 [53]

Answer:

Vy = 26 m/s sin 30 = 13 m/s      vertical speed

t = Vy / a = 13 m/s / 9.80 m/s^2 = 1.33 sec     time to reach Vy = 0

H = Vy t + 1/2 g t^2

H = 13 m/s * 1.33 sec - 1.33^2 * 9.8 / 2 m = 8.62 m

4 0
1 year ago
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