Answer:
There are 70 grams of KOH
Explanation:
First, we calculate the weight of 1 mol of KOH:
Weight 1 mol KOH: Weight K + Weight 0 + Weight H= 39g+ 1g+ 16g= 56 g/mol
1 mol-------56 g KOH
1,25 mol----x= (1,25 molx56 g KOH)/1 mol= <em>70 g KOH</em>
Answer:
12 grams
Explanation:
For any radioactive substance
the amount of substance left after n half life is given by = 
where x the original amount of substance.
____________________________________________
Half life of isotope Np-238 = 2 days
total no of days = 6
no of half life =total no of days/Half life of isotope Np-238 = 6/2 = 3
thus,
for our problem n = 3
initial amount of Np-238 = 96 grams
thus,
the amount of substance left after 3 half life = 96/2^3 = 96/8 = 12 grams.
Thus, 12 grams will be left after six days.
Answer:
Explanation:
The following precautions should be followed for a safe and efficient laboratory environment:
The TLC plate should be laid on a paper towel, to ease picking it from the bench top.
The used TLC spotters and the used TLC plates in the appropriate waste containers provided for this purpose should be placed in the blood.
Spills should be cleaned up and contaminated surfaces should be washed with water.
The pipette and/or glassware should be rinsed again with the distilled water, in case there is the slightest doubt about the contamination.
Everything used should be washed with distilled water, including the pipettes.