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3 years ago

What is a pure substance that contains only one atom called?

Chemistry

2 answers:

xxMikexx [17]3 years ago

5 0

A pure substance with only one atom is a compound

tekilochka [14]3 years ago

3 0

It's called an element.

Eg: Oxygen is an element and if we had 100g of it it would only contain Oxygen atoms.

An compound contains two or more elements such as Sodium Chloride. NaCl contains both Na and Cl atoms.

Hope this helps. Message me if you want any more help.

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) Hydrogen gas is highly combustible, and leakage can lead to a catastrophic explosion. The concentration of hydrogen gas in the

erastovalidia [21]

Answer:

Hydrogen gas is highly combustible, and leakage can lead to a catastrophic explosion. The concentration of hydrogen gas in the furnace is held constant at 6.022 x 1023 atoms/m3 and is effectively 0 outside the furnace. Calculate the mass flow rate (mg/hr) of hydrogen from the furnace if the diffusivity of hydrogen through the glass is 2 x 10-5 m2 /s. You may assume steady state behavior and constant diffusivity. You may assume that diffusion only occurs through the glass. The molar mass of hydrogen can be taken as 2 g/mol

Explanation:

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3 years ago

Identifying Changes of Matter

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2 years ago

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Tatiana [17]

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6 0

2 years ago

Which of these is the ionic compound?

ale4655 [162]

Answer:

RbF

mgo

nh4cl

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2 years ago

Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.6 g of methane is

lianna [129]

Answer:

21.6 g

Explanation:

The reaction that takes place is:

CH₄ + 2O₂ → CO₂ + 2H₂O

First we convert the given masses of both reactants into moles, using their respective molar masses:

9.6 g CH₄ ÷ 16 g/mol = 0.6 mol CH₄

64.9 g O₂ ÷ 32 g/mol = 2.03 mol O₂

0.6 moles of CH₄ would react completely with (2 * 0.6) 1.2 moles of O₂. As there are more O₂ moles than required, O₂ is the reactant in excess and CH₄ is the limiting reactant.

Now we calculate how many moles of water are produced, using the number of moles of the limiting reactant:

0.6 mol CH₄ * $\frac{2molH_2O}{1molCH_4}$ = 1.2 mol H₂O

Finally we convert 1.2 moles of water into grams, using its molar mass:

1.2 mol * 18 g/mol = 21.6 g

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2 years ago