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3 years ago

How are a grassland ecosystem and a pond ecosystem connected?

Physics

1 answer:

olga nikolaevna [1]3 years ago

6 0

Answer:

terrestrial ecosystem and pond ecosystem is an aquatic ecosytem, hence both their abiotic and biotic components would be different.

Explanation:

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A 2.4 kg block is dropped onto a spring and platform of negligible mass. The block is released

statuscvo [17]

The speed of the block when the compression is 15 cm is 9.85 m/s.

The given parameters;

mass of the block, m = 2.4 kg
height of the block, h = 5 m
compression of the spring, x = 25 cm = 0.25 m

The spring constant is calculated as follows;

$F = kx\\\\mg = kx\\\\k = \frac{mg}{x} \\\\k = \frac{2.4 \times 9.8}{0.25} \\\\k = 94.08 \ N/m$

The speed of the block when the compression is 15 cm can be determined by applying the principle of conservation of energy;

$\Delta K.E = \Delta P.E\\\\\frac{1}{2} m(v^2 - v_{0 }^2 ) = mgh - \frac{1}{2} kx^2\\\\\frac{1}{2} mv^2 = mgh - \frac{1}{2} kx^2\\\\mv^2 = 2mgh - kx^2\\\\v^2 = \frac{2mgh - kx^2}{m} \\\\v = \sqrt{\frac{2mgh - kx^2}{m}} \\\\v = \sqrt{\frac{(2 \times 2.4 \times 9.8 \times 5) - (94.08 \times 0.15^2)}{2.4}} \\\\v = 9.85 \ m/s$

Thus, the speed of the block when the compression is 15 cm is 9.85 m/s.

Learn more here:brainly.com/question/14289286

8 0

3 years ago

g calculate the effectiveness radiation dosage in sieverts for a 79 kg person who is exposed 6.8x10^9

Elza [17]

Answer:

The answer is " $\bold{dosage = 0.031 rem}$ "

Explanation:

please find the complete question in the attached file.

Given value:

$m = 79\ kg \\\\n = 3.4 \times 10^9 \\\\E = 5.5 \times 10^{-13} \\\\ RBE = 15$

$\to E = n E\\$

$= 3.4 \times 10^9 \times 5.5 \times 10^{-13} \\\\ = 1.87 \times 10^{-3}$

$\to E(absorbed) = 1.87 \times 10^{-3} \times 0.87 = 1.63 \times 10^{-3}$

calculating the radiation absorbed per kg:

$= \frac{1.63 \times 10^{-3}}{79} \\\\ = 2.06 \times 10^{-5} \\\\ = 0.00206 \ rad$

$\to Dosage = 0.00206 \times 15 \\$

$= 0.031 \ \ rem$

4 0

3 years ago

Pls help if u do it 100 points

Bumek [7]

Answer:

hhuuufuhrhuuuryheu7uhhehfu

3 0

2 years ago

Suppose a pendulum bob is swinging back and forth. If the highest point is 12.5 cm above the lowest point, what would be speed o

Colt1911 [192]

Answer:

The speed of the bob when it passes the lowest point $V = 1.57 \frac{m}{s}$

Explanation:

Given data

$H = 12.5 \ cm = 0.125 \ m\\$

When a pendulum swinging back & forth then at highest point the velocity is zero and lowest point velocity is maximum.

Velocity at lowest point is given by

$V = \sqrt{2 g H}$

$V = \sqrt{2 (9.81)(0.125)}$

$V = 1.57 \frac{m}{s}$

Therefore the speed of the bob when it passes the lowest point $V = 1.57 \frac{m}{s}$

7 0

3 years ago

Please help me! I really don't understand physics. (Please explain how you got the answers also) Thank you!

pickupchik [31]

P = Momentum
M = Mass
t = time
v = velocity (speed)
J= Impulse

1.)
F = 100N
t = 5s

Change in momentum(P) = Ft

I see that this is not one of your equations but your equations do not work with this problem.

P = Ft
P = (100)(5)
P = 500 Ns

2.)
See if you can get this one by yourself from what I did on the last problem.

3.)
P = 25 kgm/s
M = 2.0 kg

So, you are looking for velocity (speed). Look for the equation that has momentum, mass and velocity.

Use the equation P = mv

25 = 2(v)
25 = 2v
25/ 2 = 2v/2
12.5 m/s = v

4.) Do the same for number 4.
P = 12 kgm/s
M = 1kg

P = mv
12 = 1v
12/1 = 1v/1
12 m/s = v

6.)
P = 100 kgm/s
V= 7.0m/s

P= mv
100 = m7.0
100/7 = 7.0m/7
14.28 kg = m

Try page 2 by yourself and message me or comment if you need more help. Just identify the variable you have and what you need to find and put them in an equation that fits. You can do this!!!!

3 0

3 years ago