Answer:
potential enrgy U = m g L sin θ
speed V = √(2g L sin θ)
Explanation:
The expression for the gravitational potential energy of a body is
U = mg Y - mg Yo
Where Y give us a constant initial energy from which the differences are measured, for general simplicity it is selected as zero, Yo= 0
What we find an expression for height, let's use trigonometry
sin θ= Y / L
Y = l sin θ
We substitute in the power energy equation
U = m g L sin θ
2. The mechanical energy of the system is conserved, so we will write the mechanical energy at two points the highest and the lowest
Highest Em = U
Lower Em = K
U = K
m g L sin θ = ½ m v²
V = √(2g L sin θ)
the Ans is=
mp= 22.10^-6 kg
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1 mile = 1.609344 km
x miles = 95 km
x = 95 : 1.609344 = 59.03
Answer: 53.09 mph
Answer:
4miles/hour
Explanation:
the solution for this question requires that the quantities are converted to the appropriate units as required by the question.
Rate in miles per hour = distance in miles / time in hour
to convert 12 minutes to hours; recall that 60 minutes make 1 hour
12 minutes to hour = 12/60 = 0.2hr
to convert 4224 feet to miles; recall 5280 feet is equivalent to 1 mile
4224 feet to miles = 4224/5280 = 0.8 miles
∴ rate = 0.8 / 0.2
rate = 4 miles per hour
the constant rate in miles per hour = 4 miles/hour
Answer: 200 knots
Explanation: the maximum indicated airspeed at which aircraft may be flown when at or below 2,500 feet AGL and within 4 nautical miles of the primary airport of Class C airspace is 200 KNOTS
