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Ierofanga [76]
2 years ago
11

What is the mass of oxygen gas (O2) needed when 8.75 x 1070 molecules of methane (CH4) combust to form carbon dioxide (CO2)? (Ch

oose closest answer)
CH4 + 2O2 -> CO2(g) + 2H2O
A.
8.43 x 1093 grams
B.
9.299 x 1048 grams
C.
2.32 x 103 grams
D.
9.08 grams
E.
my mom
Chemistry
1 answer:
nataly862011 [7]2 years ago
4 0
It’s so easy it’s d then the carbon dioxide msmsnansnsnsjs
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Which term best describes what Donna observed?<br> A:dew<br> B:fog<br> C:mist <br> D:rain
MariettaO [177]

I also think it’s B but not quite sure

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3 years ago
- Equilibrium shifts for slightly soluble compounds The reaction for the formation of a saturated solution of silver bromide (Ag
RideAnS [48]

Answer:

1) Favor formation of reactant

2) Favor formation of product

3) Favor formation of product

4) Favor formation of product

5) Favor formation of product

Explanation:

The reaction is AgBr(s)--->Ag^{+}(aq)+Br^{-}(aq)

The reaction is endothermic

1. Adding hydrobromic acid (HBr)

It will increase the amount of bromide ion. Bromide ion is one of the product so it will favor formation of reactant.

2. Lowering the concentration of bromide (Br-) ions

As we are decreasing the the concentration of product it will favor formation of more products

3. Heating the concentrations

If we are heating the mixture, it will increase the temperature and it will favor endothermic reaction. Thus will favor formation of product.

4. Adding solid silver bromide (AgBr)

If we are adding silver bromide it means we are increasing the concentration of reactant, it will favor formation of products

5. Removing silver (Ag+) ions

Removing silver ions means we are decreasing the concentration of product thus it will favor formation of products.

3 0
3 years ago
Which of the following objects does not decompose?
Anettt [7]
B) Plastic Water Bottle
6 0
2 years ago
Read 2 more answers
If the rate of decomposition of ammonia, NH3, at 1150 K is 2.10 x 10-6 mol/L/s, what is the
Alina [70]

Answer:

3.15 × 10⁻⁶ mol H₂/L.s

1.05 × 10⁻⁶ mol N₂/L.s

Explanation:

Step 1: Write the balanced equation

2 NH₃ ⇒ 3 H₂ + N₂

Step 2: Calculate the rate of production of H₂

The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s

Step 3: Calculate the rate of production of N₂

The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s

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Pacific plate
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