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zavuch27 [327]
3 years ago
7

(for astronomy class)

Physics
2 answers:
satela [25.4K]3 years ago
8 0

Answer:

D.

Explanation:

I think don't quote me tho

Dafna11 [192]3 years ago
7 0

Answer:

d

Explanation:

astroids are not the same size so if a big astroid gets to close to a small one they will make contact or the small astroid will orbit the bigger one

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Write an equation for the nth term of the arithmetic sequence: 64, 78, 92, 106, ...
Anna [14]

If  64  is term #1 of the sequence,
then the general term is
                                      <em> T(n) = 50 + 14n </em>.


4 0
4 years ago
Which term defines the distance from the focal point to either a lens or a mirror?
Nookie1986 [14]
The focal length, like you said it's the distance between the FOCAL point and the mirror.
6 0
4 years ago
You are a project manager for a manufacturing company. One of the machine parts on the assembly line is a thin, uniform rod that
ra1l [238]

Answer:

a) I=0.012\ kg.m^2

b) I=0.012\ kg.m^2

Explanation:

Given that:

  • mass of rod, m=0.4\ kg
  • length of the rod, l=0.6\ kg

<u>(a)</u>

<u>Moment of inertia of rod about its center and perpendicular to the rod is given as:</u>

I=\frac{1}{12} m.l^2

I=\frac{1}{12} 0.4\times 0.6^2

I=0.012\ kg.m^2

(b)

<u>Moment of inertia on bending the rod to V-shape of 60 degree angle and axis being perpendicular to the plane of V at the vertex.</u>

<em>We treat it as two rod with axis of rotation at the end and perpendicular to the plane of rotation. </em>

<em>So, the mass and the length of the rod will become half of initial value.</em>

I=I_1+I_2

I=\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2 +\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2

I=2[ \frac{1}{3}\times 0.2\times 0.3^2]

I=0.012\ kg.m^2

7 0
3 years ago
A rod of 2.0-m length and a square (2.0 mm X 2.0 mm) cross section is made of a material with a resistivity of 6.0 E–8 Ohm meter
Alex Ar [27]

Answer:

8.33*10^-16 Watt

Explanation:

Given that

Length of the rod, l = 2 m,

Area of the rod, A = 2 x 2 mm² = 4*10^-6 m²

resistivity of the rod, p = 6*10^-8 ohm metre,

Potential difference of the rod, V = 0.5 V

Let R be the resistance of the rod, then

R = p * l / A

R = (6*10^-8 * 2) / (4*10^-6)

R = 3*10^14 ohm

Heat generated per second = V² / R Heat = (0.5)² / (3*10^14)

Heat = 0.25 / 3*10^14

Heat = 8.33*10^-16 Watt

Therefore, the rate at which heat is generated is 8.33*10^-16 Watt

4 0
4 years ago
Which scientist was the first to propose the heliocentric model of the universe? A. Aristotle B. Isaac Newton C. Galileo Galilei
Annette [7]

The answer would defiantly be option D "Nicolaus Copernicus." Copernicus was first to purpose the model of the universe, back in 1543 he presented a heliocentric model of the universe, he also made a geocentric model.

Hope this helps!

Nonportrit

6 0
4 years ago
Read 2 more answers
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