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zavuch27 [327]
2 years ago
7

(for astronomy class)

Physics
2 answers:
satela [25.4K]2 years ago
8 0

Answer:

D.

Explanation:

I think don't quote me tho

Dafna11 [192]2 years ago
7 0

Answer:

d

Explanation:

astroids are not the same size so if a big astroid gets to close to a small one they will make contact or the small astroid will orbit the bigger one

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calculate the mass of air in a room if the floor dimensions are 10m × 12m and height is 400 cm the density of air is 1 .26 kg/M³
Burka [1]

Explanation:

first find the volume of room --->

v \:  = 10 \times 12 \times (400 \times  {10}^{ - 2} ) \times  = 480 \:  {m}^{3}

then find the mass

mass \:  =  \: density \:  \times  \: volume \:  = 480 \times 1.26 = 604.8 \: kg

6 0
3 years ago
A solid copper cube is attached to spring-like device and is able to oscillate horizontally with negligible friction. Each side
Kazeer [188]

Answer:

6.91 Hz

Explanation:

Volume of the cube

= (1.5 x 10⁻² )³m³

= 3.375 x 10⁻⁶ m³

mass of the cube

= 3.375 x 10⁻⁶  x 8920 ( 8.92 g / cm³ = 8920 kg/m³ )

m = 30.105 x 10⁻³ kg

Spring stretches by 2.65 x 10⁻² m due to a force of  1.5 N.

If k be the force constant

k x = F

K x2.65 x 10⁻²  = 1.5

k = .566 x 10² N / m

Now frequency of oscillation for spring - mass system is given by

n = \frac{1}{2\pi} \sqrt{\frac{k}{m} }

=\frac{1}{2\pi} \sqrt{\frac{56.6}{.03} }

n = 6.91 Hz

4 0
3 years ago
Maya and Kenzie are discussing oil spills and how they impact the environment. How can humans help reduce the impact of oil spil
madam [21]

The correct answer is A.

6 0
2 years ago
Read 2 more answers
the average time required for radioactive elements, whereby they decay to half their original mass is called the "average life"
VikaD [51]
I'm not sure what your question is. But, the half life is the amount of time required for half the material to decay. For U238 this is 4.5 billion years, whilst for Fr-223 (Francium) its about 22 minutes. To calculate the time for something to decay you need to use the equation:
Mass (after time t) = Mass (initial) * (0.5)^(time/half life)
Hope this helps
4 0
3 years ago
Read 2 more answers
A point charge is placed at each corner of square with side leanth a. The charges all have same magnitude q. My question, What i
nexus9112 [7]

Answer:

 E = k q / a²   (1.3535) (- i ^ + j ^)

  E = k q / a²  1.914  ,      θ’= 135

Explanation:

For this exercise we will use Newton's second law where we must add as vectors

        E_total = E₁₂ i ^ + E₁₄ j ^ + E₁₃

Let's look for the value of each term

On the x axis

       E₁₂ = k q / a²

On the y axis

       E₁₄ = k q / a²

For the charge in the opposite corner we look for the distance

        d = √ (a² + a²) = a √2

let's look for the field

      E₁₃ = k q / d²

      E₁₃ = k q / 2a²

let's use trigonometry to find the two components of this field

       cos 45 = E₁₃ₓ / E₁₃

       E₁₃ₓ = E₁₃ cos 45

       

       sin 45 = E_{13y} / E₁₃

       E_{13y} = E₁₃ sin 45

       E₁₃ₓ = k q / 2a²  cos 45

       E_{13y} = k q / 2a²  sin 45

let's find each component of the electric field

X axis

      Eₓ = -E₁₂ - E₁₃ₓ

      Eₓ = - k q / a² - k q / 2a² cos 45

      Eₓ = - k q / a² (1 + cos 45/2)

      cos 45 = sin 45 = 0.707

      Eₓ = - k q / a²   (1 + 0.707 / 2)

      Eₓ = - k q / a²    (1.3535)

Y axis  

      E_y = E₁₄ + E_{13y}

       E_y = k q / a² + k q / 2a²     sin 45

       E_y = k q / a² (1 + sin 45/2)

       E_y = k q / a²       (1.3535)

we can give the results in two ways

       E = k q / a²   (1.3535) (- i ^ + j ^)

In modulus and angle form, let's use Pythagoras' theorem for the angle

       E = √ (Eₓ² + E_y²)

        E = k q / a²    1.3535 √2

        E = k q / a²     1.914

we use trigonometry for the angle

        tan θ = E_y / Eₓ

         θ = tan⁻¹  (E_y / Eₓ)

         θ = tan⁻¹ (1 / -1)

         θ = 45

in the third quadrant, if we measure the angle of the positive side of the x-axis

           θ‘= 90 + 45

           θ’= 135

4 0
3 years ago
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