<span>(a) 39.5 g
(b) 49.53 cm^3
(c) 0.7975 g/cm^3, liquid is an alcohol
(a) This will be the difference between the weight of the iron in air and the weight submerged in fluid. So:
390.0 g - 350.5 g = 39.5 g
(b) The density of iron is 7.874 g/cm^3, so the volume of the iron chunk is
390.0 g / 7.874 g/cm^3 = 49.53 cm^3
(c) The density of the fluid will be the mass of the fluid divided by the volume, so:
39.5 g / 49.53 cm^3 = 0.7975 g/cm^3
Since the density is very dependent upon the temperature and since the temperature wasn't specified, the actual substance can't be completely identified. Although some candidates are:
1. Mixture of Alcohol and water. Density ranges from 0.785 g/cm^3 to 1.000 g/cm^3.
2. Crude oil. Density 0.790 g/cm^3
3. Hydrazine. Density 0.795 g/cm^3
4. Methanol. Density 0.791 g/cm^3
5. Ocimene. Density 0.798 g/cm^3
The most likely candidate is a high concentration of an alcohol of some sort.</span>
Answer:
h = 6.371 m
Explanation:
Data:
Potential Energy = P.E = 1500 J
Mass = m = 24 Kg
Gravity = g = 9.81 m/sec²
Height = h = ?
Solution:
As the formula for the Potential Energy is;
P.E = mgh
Replacing the values in the above equation
1500 = 24 × 9.81 × h
h = (1500)÷(24 × 9.81)
h = 6.371 m
It is a synthesis reaction where two reactants gives one product.
Answer:option D
2Mg + O2 ------> 2 MgO
<u>series </u>
current same to all resistors
p.d is divided to each resistors depending on their resistivity
V = IR the resistor which have more resistance (also resistivity) gain more p.d
<u>parallel
</u> p.d is same to all components
<u /> current is divided to each resistor depending on their resistivity
I = V/R more current flows through one with less resistance (also resistivity)
here as it is series connection,<u>current is same</u> to all resistors irrespective of their resistance
We are given the mass of an <span>aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47</span>
