The cart will be pulled to the right by the hanging mass, so by Newton's second law, the net force on the cart is
<em>T</em> - 25 N = (8 kg) <em>a</em>
where <em>T</em> is the tension in the rope and <em>a</em> is the acceleration.
The hanging mass has a net force of
(6 kg) <em>g</em> - <em>T</em> = (6 kg) <em>a</em>
where <em>g</em> = 9.8 m/s².
Adding these equations together eliminates <em>T</em>, and we can solve for <em>a</em> :
(<em>T</em> - 25 N) + ((6 kg) <em>g</em> - <em>T </em>) = (14 kg) <em>a</em>
33.8 N = (14 kg) <em>a</em>
<em>a</em> = (33.8 N) / (14 kg) ≈ 2.4 m/s²
Then the tension in the rope is
<em>T</em> - 25 N = (8 kg) (2.4 m/s²)
<em>T</em> ≈ 25 N + 19.31 N ≈ 44 N
