A 110 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.220 m/s. How much work must be d
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Answer:
1) Mass that needs to be converted at 100% efficiency is 0.3504 kg
2) Mass that needs to be converted at 30% efficiency is 1.168 kg
Explanation:
By the principle of mass energy equivalence we have
where,
'E' is the energy produced
'm' is the mass consumed
'c' is the velocity of light in free space
Now the energy produced by the reactor in 1 year equals
Thus the mass that is covertred at 100% efficiency is
Part 2)
At 30% efficiency the mass converted equals
Taking specific heat of lead as 0.128 J/gK = c
We have energy of ball at 7.00 meter height = mgh =
When leads gets heated by a temperature ΔT energy needed = mcΔT
= ΔT
Comparing both the equations
=
ΔT
ΔT = 0.536 K
Change in temperature same in degree and kelvin scale
So ΔT = 0.536