Show by calculation which process produces more energy per gram of material reacting

Chemistry

1 answer:

valina [46]4 years ago

8 0

The answer is meaw meaw

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When warm air is forced upward along a cold front what might happen?

mote1985 [20]

Answer: With the cold front, warm air is rapidly forced upward (like the shavings) in advance of the actual front (the “cutter”), creating towering cumulus clouds, some hard showers and quite possibly a few gusty thunderstorms followed by a push of cooler and drier air in its wake.

Explanation:

8 0

3 years ago

PLEASE HELP ME

Dmitriy789 [7]

Hello!

The ball took up 2,9L

To solve this problem, we should apply the ideal gas law and clear for n (the number of moles), as this value doesn't change when Devin takes the ball to the garage:

$n= \frac{P1*V1}{RT1}=\frac{P2*V2}{RT2}$

Now, we should clear this equation to find V2, as this is the value we are looking for:

$V2= \frac{P1*V1*T2}{P2*T1}= \frac{400kPa*3L*250K}{350kPa*300K}=2,857L$ ≈2,9L

Have a nice day!

6 0

3 years ago

Hydrocarbons are compounds that contain

Mademuasel [1]

2) carbon and hydrogen only.

3 0

4 years ago

Compound decomposes through the following unbalanced reaction in acidic media: MnO2→ MnO4-(s) + Mn2+(s) Balance this reaction an

choli [55]

Answer:

C) MnO₂

Explanation:

If we write the semi equations (this is, for reduction and oxidation) we will have:

Oxidation: 2MnO₂ → MnO₄⁻ + Mn⁺²

Reduction: 2H₂O → H₂ + 2OH⁻

Then the final global reaction (just adding the two above hemi chemical reactions):

2MnO₂ + 2H₂O → MnO⁻₄ + Mn⁺² + H₂ + 2OH⁻ (in acidic media)

So, we have Mn⁺⁴ (from MnO₂) goes to Mn⁺⁷ and Mn⁺² (this is, Mn is oxidated) and H⁺ (from acidic media or H₂O) goes to H₂ (this is, it is reduced). So the reducing agent would be MnO₂

7 0

4 years ago

2KCIO3 ----------> 2KCI + 302<br> How many moles of KCIO3 are needed to make 3.5 moles of KCL?

lyudmila [28]

Answer:

3.5 mol KClO3

Explanation:

Given 3.50 moles of KCl as the target amount in the problem, used the coefficient of the balanced chemical reaction involved to determine the number of moles of potassium perchlorate needed.

x mole of KClO3 = 3.5 mol KCl x [(2 mol KCl)/ (2 mol KClO3)] = 3.5 mol KClO3

x mole of KClO3 = 3.5 mol KClO3

3 0

3 years ago