Answer:
flow rate is 8.0385 × 
m³/s or 12.741 gpm
Explanation:
given data
12-nominal schedule 40 pipe
Reynolds number = 2000
to find out
What is the flow rate
solution
we know the diameter of 12-nominal schedule 40 pipe is
Diameter = 12.75 inch
D = 0.32385 m
and
dynamic viscosity of Turpentine is = 0.001375 Pa-s
and Density of Turpentine is 870 kg/m³
so
Reynolds number is express as
Re = 
here ρ is density and D is diameter and V is velocity and µ is viscosity
so put here all value
2000 = 
V = 9.7619 × 
m/s
and
flow rate is
Q = V × A
here A is area and Q is flow rate
Q = 9.7619 × × 
Q = 8.0385 × m³/s
so flow rate is 8.0385 × m³/s or 12.741 gpm
so the answer is f because your a faliure so get out of here you fatty
Answer:
The correct answers are:
a. % w = 33.3%
b. mass of water = 45g
Explanation:
First, let us define the parameters in the question:
void ratio e = 
= 
Specific gravity 
= 
% Saturation S = 
× 
= 
× 
water content w = 
= 
a) To calculate the lower and upper limits of water content:
when S = 100%, it means that the soil is fully saturated and this will give the upper limit of water content.
when S < 100%, the soil is partially saturated, and this will give the lower limit of water content.
Note; S = 0% means that the soil is perfectly dry. Hence, when s = 1 will give the lowest limit of water content.
To get the relationship between water content and saturation, we will manipulate the equations above;
w = 
Recall; mass = Density × volume
w = 
From eqn. (2) = 
∴ 
putting eqn. (6) into (5)
w = 
Again, from eqn (1)
substituting into eqn. (7)
∴ 
With eqn. (7), we can calculate
upper limit of water content
when S = 100% = 1
Given, 
∴
∴ %w = 33.3%
Lower limit of water content
when S = 1% = 0.01
∴ % w = 0.33%
b) Calculating mass of water in 100 cm³ sample of soil (
)
Given, 
, S = 50% = 0.5
%S = 
× = 
×
0.50 = 
mass of water = 
Answer:
The heat transferred to water equals 1600 kJ
Explanation:
By the conservation of energy we have
All the kinetic energy of the moving vehicle is converted into thermal energy
We know that kinetic energy of a object of mass 'm' moving with a speed of 'v' is given by
Thus
Thus the heat transferred to water equals 
