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IrinaK [193]
3 years ago
6

The ... in an atom move about in the space surrounding the nucleus

Physics
1 answer:
Stolb23 [73]3 years ago
6 0
Electrons

the in an atom move about in the space surrounding the nucleus
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1<br> 1. Hydrogen's one electron is found in the<br> energy level.<br> ок<br> O<br> L<br> OM
inn [45]

Answer:

Energy Level K

Explanation:

In electronic configuration there are four shells named <em>KLMN</em><em> </em> which hold 2 , 8 , 18 , 32 electrons respectively.

3 0
3 years ago
Two point charges are on the y axis. A 4.50-σC charge is located at y=1.25 cm , and a -2.24-σC charge is located at y=-1.80 cm.
kvasek [131]

Two point charges are on the y axis. A  4.50-σC charge (q_1) is located at y=1.25 cm (r_1) , and a -2.24-σC charge (q_2) is located at y=-1.80 cm (r_2).

The total electric potential at the origin is 2.12\times10^6V.

How to calculate the total electric potential at the origin?

The total electric potential at some point due to several point charges is represented by:

V=k_e  \sum _i \frac{q_i}{r_i}

Here,

k _e= 8.988 \times 10^9 N \cdot m^2/C^2 (Columbic constant)

The total electric potential at point O is the sum of the potentials due to q_1 and q_2 will be:

V_O=k_e(\frac{q_1}{r_1} +\frac{q_2}{r_2} )

Substituting the values, we get:

V_O=8.988\times10^9(\frac{4.5 \times 10^{-6}}{0.0125} +\frac{-2.24\times10^{-6}}{0.018} )=2.12\times10^6V

Hence, the total electric potential at the origin is2.12\times10^6V.4

To learn more about total electric potential, refer to:

brainly.com/question/16843018

#SPJ4

8 0
2 years ago
The fundamental frequency of a guitar string is 367 hz . part a what is the fundamental frequency if the tension in the string i
ANTONII [103]
The fundamental frequency of a string is given by:
f_1 =  \frac{1}{2L} \sqrt{ \frac{T}{\mu} }
where L is the string's length, T the tension and \mu the linear density of the string.

We can see that f1 is proportional to the square root of T: \sqrt{T}.
This means that if the new tension is half the initial value, the new fundamental frequency will be proportional to \sqrt{ \frac{T}{2} }= \frac{ \sqrt{T} }{ \sqrt{2} }=  \frac{f_1}{ \sqrt{2} }

So, the new fundamental frequency will be
f_1 ' =  \frac{367 Hz}{ \sqrt{2} }=259.5 Hz
6 0
4 years ago
Since acids are so corrosive they are not found anywhere in the human body true/false
pantera1 [17]

the answer is in fact True

5 0
4 years ago
Read 2 more answers
How long is a year on Earth and what journey does the Earth make in this space of time?
FrozenT [24]
A year on Earth is 365 and 1/4 days (rounded).  It corresponds to
one revolution of the Earth in our orbital path around the sun.
8 0
3 years ago
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