The period of physical changes to sex characteristics that marks the beginning of adolescence in males and females is Puberty.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
![W = 121271.99 \ J](https://tex.z-dn.net/?f=W%20%3D%20121271.99%20%5C%20%20J)
b
![v = 26.74 \ m/s](https://tex.z-dn.net/?f=v%20%20%3D%2026.74%20%5C%20%20m%2Fs)
Explanation:
From the question we are said that
The mass of the shed is ![m_s = 375 \ kg](https://tex.z-dn.net/?f=m_s%20%20%3D%20%20375%20%5C%20%20kg)
The pulling force is
The angle is ![\theta = 15^o](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%2015%5Eo)
The distance covered is
The kinetic force is ![F_k = 255 \ N](https://tex.z-dn.net/?f=F_k%20%20%3D%20%20255%20%5C%20%20N)
Generally the work done is mathematically represented as
![W = F * cos(\theta ) * d](https://tex.z-dn.net/?f=W%20%3D%20%20F%20%2A%20cos%28%5Ctheta%20%29%20%2A%20d)
=> ![W = 2511 * cos( 15 ) * 50](https://tex.z-dn.net/?f=W%20%3D%202511%20%2A%20cos%28%2015%20%20%29%20%2A%20%2050)
=> ![W = 121271.99 \ J](https://tex.z-dn.net/?f=W%20%3D%20121271.99%20%5C%20%20J)
Generally according to the work-energy theorem
![T_w = \Delta KE](https://tex.z-dn.net/?f=T_w%20%3D%20%20%5CDelta%20%20KE)
Here
is total work done which is mathematically represented as
![T_w = F_k * d + F d cos(\theta)](https://tex.z-dn.net/?f=T_w%20%3D%20%20F_k%20%2A%20%20d%20%20%2B%20%20F%20d%20cos%28%5Ctheta%29)
=> ![T_w = 255 * 50 + 121271.99](https://tex.z-dn.net/?f=T_w%20%3D%20%20%20255%20%20%2A%20%20%2050%20%20%20%2B%20121271.99)
=> ![T_w = 134021.99 \ J](https://tex.z-dn.net/?f=T_w%20%3D%20%20%20134021.99%20%5C%20%20J)
Also
is the change in kinetic energy which is mathematically represented as
![\Delta KE = \frac{1}{2} * m * [ v^2 - u^0 ]](https://tex.z-dn.net/?f=%5CDelta%20%20KE%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20%20m%20%2A%20%20%5B%20v%5E2%20-%20%20u%5E0%20%5D)
Here u is the initial velocity of the shed when at rest
![\Delta KE = \frac{1}{2} * 375 * [ v^2 - 0^0 ]](https://tex.z-dn.net/?f=%5CDelta%20%20KE%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%20375%20%20%2A%20%20%5B%20v%5E2%20-%20%200%5E0%20%5D)
=> ![\Delta KE = 187.5 v^2](https://tex.z-dn.net/?f=%5CDelta%20%20KE%20%20%3D%20%20187.5%20%20v%5E2)
So
![134021.99 = 187.5 v^2](https://tex.z-dn.net/?f=134021.99%20%20%3D%20%20%20187.5%20%20v%5E2)
=> ![v = \sqrt{714.783 }](https://tex.z-dn.net/?f=v%20%20%3D%20%20%5Csqrt%7B714.783%20%7D)
=> ![v = 26.74 \ m/s](https://tex.z-dn.net/?f=v%20%20%3D%2026.74%20%5C%20%20m%2Fs)
Answer:
it's true
Explanation:
according to the periodic table
Answer:
approximately 0.00504 kWh
Explanation:
This electrical energy and is measured in kWh.
For 5 minutes and 20 seconds of use, it is 0.06 W x 0.084 h = 0.00504 kWh.
<u><em>Note</em></u>: 60W = 0.06kW; 5min 20sec = 0.083(8) ≈ 0.084 hour