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3 years ago

A car accelerates from 20 m/s to 80 m/s in 5 seconds. What is the

Physics

1 answer:

Fofino [41]3 years ago

8 0

Answer:

12m/s2

Explanation:

:D (just a smiley, not answer d)

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Two 5000-kg passenger cars roll without friction (one at 1 m/s, the other at 2 m/s) toward one another on a level track. They co

balu736 [363]

The combined momentum of the passengers is 5000 kgm/s.

<h3>Combined momentum of the passenger</h3>

The combined momentum of the passengers is calculated as follows;

P = mv1 + mv2

where;

m is mass of the passengers
v1 is velocity of the first passenger
v2 is velocity of the second passenger

P = m(v1 + v2)

P = 5000(-1 + 2)

P = 5000 kgm/s

Thus, the combined momentum of the passengers is 5000 kgm/s.

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5 0

2 years ago

What’s the origin of a meteor shower?

Bogdan [553]

Answer: I hope this helps I read this in a book once

Explanation:

Shower meteors come from the dust released by comets as they travel through our solar system. The dust spreads out along the comet's orbit and forms an elliptical trail of debris that passes around the sun and crosses the orbits of the planets.

6 0

3 years ago

Helppppppp its exam

UkoKoshka [18]

Answer:

a. 240.2 C

Explanation:

7 0

3 years ago

5. Kelvin applied a rightward force of 302 N to a 29 kg desk to accelerate it across the floor. The

Naddik [55]

The force of friction is 213.2 N

Explanation:

The frictional force acting on an object sliding on a surface is given by:

$F_f = \mu mg$

where:

$\mu$ is the coefficient of friction

m is the mass of the object

g is the acceleration of gravity

In this problem we have

$\mu=0.750$

m = 29 kg

$g=9.8 m/s^2$

Therefore, the force of friction is

$F_f = (0.750)(29)(9.8)=213.2 N$

Learn more about friction:

brainly.com/question/6217246

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3 0

3 years ago

3. Una cuerda de guitarra tiene 60 cm de longitud y una masa de 0.05 kg de masa. Si se tensiona mediante una fuerza de 20 N. La

jok3333 [9.3K]

Answer:

f1 = 12.90 Hz

Explanation:

To calculate the first harmonic frequency you use the following formula for n = 1:

$f_n=\frac{n}{2L}\sqrt{\frac{T}{M/L}}$

$f_1=\frac{1}{2L}\sqrt{\frac{T}{M/L}}$ ( 1 )

It is necessary that the unist are in meters, then you have:

L: length of the string = 60cm = 0.6m

M: mass of the string = 0.05kg

T: tension on the string = 20 N

you replace the values of L, M and T in the expression (1) for getting f1:

$f_1=\frac{1}{2(0.6m)}\sqrt{\frac{20N}{0.05kg/0.6m}}=12.90\ Hz$

Hence, the first harmonic has a frequency of 12.90 Hz

4 0

3 years ago