Answer:
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Answer : The amount of heat released, -35057 J
Solution :
Process involved in the calculation of heat released :
Now we have to calculate the amount of heat released.
where,
Q = amount of heat released = ?
m = mass of water = 18 g
= specific heat of liquid water =
= enthalpy change for condensation = -40700 J/mole
Now put all the given values in the above expression, we get
Therefore, the amount of heat released, -35057 J
Option D is the correct answer , 13.5gm of precipitate would result if 50 grams of NaCl at 10 degrees Celsius and its cooled to saturation.
<h3>What is Solubility ?</h3>
the maximum quantity of a substance that will dissolve in a certain quantity of water at a specified temperature.
From the Solubility Graph of NaCl , we can see that the solubility of NaCl at 10 C is around 36.5gm/L.
If it is cooled down to saturation we will see the precipitate forming and that will be equal to the difference of solute present and the solubility.
As it is given that 50gm of solute is present
The precipitate will be 50- 36.5 gm, = 13.5 gm.
Therefore Option D is the correct answer , 13.5gm of precipitate would result if 50 grams of NaCl at 10 degrees Celsius and its cooled to saturation.
To know more about Solubility
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Answer:
The temperature is very hot.
Explanation:
The gas around the planet traps the suns heat and makes it the hottest planet in our solar system.
Answer:
Following are the solution to the given question:
Explanation:
Please find the complete question and its graph file in the attachment file.
The isomer having Z specification from around dual connector as well as the chiral center S structure is:
An 'H' atom has been at the level of 3rd carbon, and we need to change its configuration, through 'R' to 'S' by CIP notation (under contrast to -OH group).