All categories

3 years ago

Write a word equation for the combustion of propane??? HELP????

Chemistry

1 answer:

frutty [35]3 years ago

8 0

Answer:

1 mole of propane combines with 5 moles of oxygen gas to produce 3 mole of carbon dioxide and 4 moles of water.

Explanation:

The word equation for the combustion of propane can be obtained from the chemical equation;

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

The word equation is therefore:

1 mole of propane combines with 5 moles of oxygen gas to produce 3 mole of carbon dioxide and 4 moles of water.

For such a combustion reaction, carbon dioxide and water are produced in the process.

You might be interested in

The 4 in formula 4H2O is a 1. coefficient 2. subscript 3. superscript 4. binomial

Rom4ik [11]

1. Coefficient

Since it is a number that constant for the given substance

7 0

3 years ago

A 44.0mg sample of carbon reacts with sulfur to form 122 mg of the compound.

anygoal [31]

Answer:

Empirical formula = C₃S₂

Explanation:

Given data:

Mass of carbon = 44.0 mg (44/1000 = 0.044 g)

Mass of sulfur = 122 mg - 44.0 mg = 78 mg = 78/1000 = 0.078 g)

Empirical formula = ?

Solution:

First of all we will calculate the number of moles.

Number of moles of carbon = mass / molar mass

Number of moles of carbon = 0.044 g/ 12.01 g/mol

Number of moles of carbon = 0.0037 mol

Number of moles of sulfur:

Number of moles = mass / molar mass

Number of moles = 0.078 g/ 32,066 g/mol

Number of moles = 0.0024 mol

Now we will compare the moles:

C : S

0.0037/0.0024 : 0.0024/0.0024

1.5 : 1

C : S = 2(1.5 : 1)

C : S = 3 : 2

Empirical formula = C₃S₂

4 0

3 years ago

Bromine (Br2) is produced by reacting HBr with O2, with water as a byproduct. The O2 is part of an air (21 mol % O2, 79 mol % N2

Karolina [17]

Answer:

The mole fractions:

$x_{HBr}=\frac{100mol}{318.5}=0.314$

$x_{Br_2}=\frac{78mol}{318.5}=0.245$

$x_{H_2O}=\frac{78mol}{318.5}=0.245$

$x_{O_2}=\frac{62.5mol}{318.5}=0.196$

Explanation:

The reaction described is:

$2 HBr (g) + 1/2 O_2 (g) \longrightarrow Br_2 (g) + H_2O (g)$

The limiting reactant is the HBr (oxygen is in excess).

a) The mass (in moles) balance for this sistem:

$n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *n_{HBr}*0.78$

(the 0.78 is because of the fractional conversion)

$n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *n_{HBr}*1.25$

(the 1.25 is because of the oxygen excess)

$n_{H_2O}=\frac{ 1 mol H_2O}{1 mol Br_2} *n_{Br_2}$

There is only one degree of freedom in this sistem, you can either deffine the moles of HBr you have or the moles of Br2 you want to produce. The other variables are all linked by the equations above.

b) Base of calculation 100 mol of HBr:

$nn_{HBr}=100 mol HBr$

$n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *100mol HBr*0.78$

$n_{Br_2}=78 mol Br2$

$n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *100 mol HBr*1.25$

$n_{O_2}=62.5 mol O_2$

$n_{H_2O}=n_{Br_2}= 78 mol$

$n_{total}=(78+78+100+62.5)mol= 318.5mol$

The mole fractions:

$x_{HBr}=\frac{100mol}{318.5}=0.314$

$x_{Br_2}=\frac{78mol}{318.5}=0.245$

$x_{H_2O}=\frac{78mol}{318.5}=0.245$

$x_{O_2}=\frac{62.5mol}{318.5}=0.196$

4 0

3 years ago

Help me with this now please due in 20 mins

user100 [1]

Ca(oh) 2 is calcium hydroxide
So
Calcium in one box
Hydroxide in the other.
Hope this helps!

8 0

3 years ago

Which statement describes how a basic coffee cup calorimeter works? A) It measures the mass of a substance given the specific he

fomenos

A calorimeter experiment is a set-up that provides insulation so that no heat escapes to the surroundings and all energy can be accounted for. It can be done at either constant volume or constant pressure. So, the answer to this is knowing the mass of water, the specific heat which is an empirical data, and the change in temperature which can be measured using a thermometer. This experiment could measure the mass of an unknown substance added or the specific heat of the substance or the calorimeter. The answer is D.

5 0

3 years ago

Read 2 more answers