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Verdich [7]
3 years ago
9

A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over

Chemistry
1 answer:
hoa [83]3 years ago
8 0
B. Molecules in both the metal and the surrounding air will start moving at higher speeds.
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Gas A is Carbon Dioxide
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Which of the following is an example of a situation where work occurs?
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Answer:

D is the answer may be. I'm not sure.

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Why is peer review an important part of the scientific process?
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I would say B.

Explanation: Peer review improves the quality of research papers.

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Given the reaction:
tino4ka555 [31]

4 moles of NaCl is produced from 2 moles of Na₂CrO₄.

<u>Explanation:</u>

Given reaction is

PbCl₂(aq) + Na₂CrO₄(aq)→ PbCrO₄(s) + 2 NaCl (aq)

It is the balanced equation which means that on both sides of the equation, number of atoms of each element are equal.

From the above balanced equation it says that molar ratio of Na₂CrO₄ to NaCl is 1 : 2.

That is 1 mole of Na₂CrO₄ produces 2 moles of NaCl, so the molar ratio is 1:2.

2 moles of Na₂CrO₄  produces 4 moles of NaCl.

So the molar ratio of Na₂CrO₄ to NaCl is 2: 4.

6 0
3 years ago
48g of 02 produce how many grams of Al2O3
bixtya [17]

Taking into account the reaction stoichiometry,  102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

4 Al + 3 O₂  → 2 Al₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Al: 4 moles
  • O₂: 3 moles
  • Al₂O₃: 2 moles

The molar mass of the compounds is:

  • Al: 27 g/mole
  • O₂: 32 g/mole
  • Al₂O₃: 102 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Al: 4 moles ×27 g/mole= 108 grams
  • O₂: 3 moles ×32 g/mole= 96 grams
  • Al₂O₃: 2 moles ×102 g/mole= 204 grams

<h3>Mass of Al₂O₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 96 grams of O₂ form 204 grams of Al₂O₃, 48 grams of O₂ form how much mass of Al₂O₃?

mass of Al_{2} O_{3} =\frac{48 grams of O_{2} x204 grams of Al_{2} O_{3}}{96 grams of O_{2}}

<u><em>mass of Al₂O₃= 102 grams</em></u>

Finally, 102 grams of Al₂O₃ are formed when 48 grams of O₂ react.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

3 0
2 years ago
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