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bija089 [108]
3 years ago
9

Technician A says a sway bar is used to control body lean when cornering.

Engineering
1 answer:
vodka [1.7K]3 years ago
6 0

Answer:

technician B

Explanation:

because adding leaves increasing capacity

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Race cars at the Indianapolis Speedway average speeds of 185 mi/h. After determining the altitude of Indianapolis, find the Mach
denis23 [38]

Answer:

- the Mach number is 0.24.

- Compressibility becomes effective when Mach number is greater than 0.3, the Mach number of the race cars is less than 0.3, hence, compressibility will not affect their aerodynamics.

Explanation:

Given the data in the question;

Average speed V = 185 miles per hour = ( 185 /2.237 ) m/s = 82.7 m/s

From Almanac, we can find that Indianapolis is at 220 m altitude.

So from table, at that altitude, the standard speed of sound will be 339.4 m/s .

Mach number of the race car will be;

Mach Number = Velocity / sound speed

we substitute

Mach Number = ( 82.7 m/s ) / ( 339.4 m/s )

Mach Number = 0.24

Therefore the Mach number is 0.24.

We know that, compressibility becomes effective when the Mach number is greater than 0.3.

Since the Mach number of the race cars is less than 0.3, compressibility will not affect their aerodynamics.

 

8 0
3 years ago
Which best describes the body in terms of simple machines?
alex41 [277]

Answer:B

Explanation:

5 0
4 years ago
6. Construct a neural network that computes the XOR function of two inputs. Make sure to specify what sort of units you are usin
IgorC [24]

Answer:

Figure 1 shows the neural network that computes the XOR of two inputs.

Two Input unit: X₁ and X₂

One hidden layer with two hidden units: h₁ and h₂

Two Weights for hidden unit 1 = 20, 20

Bias for hidden unit 1 = -10

Two Weights for hidden unit 2 = -20, -20

Bias for hidden unit 2 = 30

Weights for output layer = 20, 20

Bias for output layer = -30

Activation function = sigmoid (σ)

Output at hidden unit and at the output unit Y is shown in Table attached in Fig 2

3 0
3 years ago
Explain the difference between the connection of a cumulative compound and a differential compound motor
Alexandra [31]

Answer:

Explanation:

A motor is a device that directs current in electrical energy form to mechanical energy, which is known as direct current (DC) motors.

DC motors are of three types: (a) The series motor, (b) The shunt motor, and (c) the compound motor. Our main focus here is the Compound motor, which is further sub-divided into:

i) The cumulative compound motors

ii) The differential compound motors

The difference between these two are:

Cumulative compound motors                  Differential compound motors

In cumulative compound motors,              In differential compound motors,

both the series and shunt windings          both series and shunt are

are connected in a way that,                     connected in a way that the

production of fluxes through them           production of fluxes via them

assist each other i.e. they aid each          always opposes each other i.e.

other in the production of magnetism      they oppose each other in the

                                                                    production of magnetism.

6 0
3 years ago
Source 1 can supply energy at the rate of 11000 kJ/min at 310°C. A second Source 2 can supply energy at the rate of 110000 kJ/mi
VladimirAG [237]

Answer:

Source 2.

Explanation:

The efficiency of the ideal reversible heat engine is given by the Carnot's power cycle:

\eta_{th} = 1 - \frac{T_{L}}{T_{H}}

Where:

T_{L} - Temperature of the cold reservoir, in K.

T_{H} - Temperature of the hot reservoir, in K.

The thermal efficiencies are, respectively:

Source 1

\eta_{th} = 1 - \frac{311.15\,K}{583.15\,K}

\eta_{th} = 0.466 \,(46.6\,\%)

Source 2

\eta_{th} = 1 - \frac{311.15\,K}{338.15\,K}

\eta_{th} = 0.0798 \,(7.98\,\%)

The power produced by each device is presented below:

Source 1

\dot W = (0.466)\cdot (11000\,\frac{kJ}{min})\cdot (\frac{1\,min}{60\,s} )

\dot W = 85.433\,kW

Source 2

\dot W = (0.0798)\cdot (110000\,\frac{kJ}{min})\cdot (\frac{1\,min}{60\,s} )

\dot W = 146.3\,kW

The source 2 produces the largest amount of power.

8 0
3 years ago
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