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3 years ago

What two factors directly affect the acceleration of an object?

1 answer:

4 0

The acceleration of an object depends on the mass of the object and the amount of the force applied to it. It states that the acceleration of an object increases with increased force and decreases with increased mass.

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Which of the following describes the pathway that nerve impulses travel while throwing a baseball

AlladinOne [14]

My Best answer would be neuron, spinal, cord, motor neuron, muscles.

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3 years ago

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In an open circuit like the picture

Dmitry_Shevchenko [17]

C. The light bulb will be off
This is due to the reason that the wire doesn’t go back to the battery :)

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3 years ago

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As best you can, describe how we can tell the age of the Earth and rocks found on it.

Viktor [21]

Answer:

We can determine the age of the Earth and the rocks found on Earth with techniques such as measuring ice cores and digging and analysing fossils.

Explanation:

Hopefully this helped!

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3 years ago

A coffee mixture has beans that sell for $0.72 a pound and beans that sell for $0.52. If 110 pounds of beans create a mixture wo

Burka [1]

X is a weight of the beans that sells for $0.72 apound
y is a weight of the beans that sells for $0.52 a pound
{x+y=110
{0.72x+0.52y=110*0.74

x=110-y
0.72*(110-y)+0.52y=81.4
79.2-0.72y+0.52y=81.4
-0.2y=2.2

Just use 110 pounds of beans that cost $0.52 and your revenue will be
30 percents
Or use 110 pounds of beans that cost $0.72 and your revenue will be
2.7 percents

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4 years ago

What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8~\mathrm{m/s^2}g=9.8 m/s 2 ) towards the Eart

Wittaler [7]

Answer:

The centripetal acceleration as a multiple of $g=9.8 m/s^{2}$ is $1.020x10^{-3}m/s^{2}$

Explanation:

The centripetal acceleration is defined as:

$a = \frac{v^{2}}{r}$ (1)

Where v is the velocity and r is the radius

Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:

$v = \frac{2 \pi r}{T}$ (2)

Where r is the radius and T is the period.

For this case the person is standing at a latitude $71.9^{\circ}$ . Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.

It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.

$\cos \theta = \frac{adjacent}{hypotenuse}$

$\cos \theta = \frac{r_{71.9^{\circ}}}{r_{e}}$ (3)

Where $r_{71.9^{\circ}}$ is the radius at the latitude of $71.9^{\circ}$ and $r_{e}$ is the radius at the equator ( $6.37x10^{6}m$ ).

$r_{71.9^{\circ}}$ can be isolated from equation 3:

$r_{71.9^{\circ}} = r_{e} \cos \theta$ (4)

$r_{71.9^{\circ}} = (6.37x10^{6}m) \cos (71.9^{\circ})$

$r_{71.9^{\circ}} = 1.97x10^{6} m$

Then, equation 2 can be used

$v = \frac{2 \pi (1.97x10^{6} m)}{24h}$

Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.

$T = 24h . \frac{3600s}{1h}$ ⇒ $84600s$