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Bogdan [553]
3 years ago
7

Our entire ______ _____ is built in the backbone of metals.

Physics
1 answer:
Aliun [14]3 years ago
6 0

Answer:

modern world

Explanation:

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If 12 coulombs of electric charge pass a point in 4.0
zubka84 [21]

Answer:

AS

Explanation:

6 0
3 years ago
1.Is it true to say that, current decreases when passing through a resistor and then increases again upon exiting?
siniylev [52]
1. Yes, this true as voltage remains constant.
2. Yes, a moving electrical charge generates a magnetic field.
8 0
3 years ago
_____ are both ways of preserving current energy resources.
MakcuM [25]

Answer:

4

Explanation:

I think if not. I am sorry

3 0
3 years ago
While moving in, a new homeowner is pushing a box across the floor at a constant velocity. The coefficient of kinetic friction b
Citrus2011 [14]

Answer:

\theta = 66.7 degree

Explanation:

since force is applied downwards at some angle with the horizontal

so here we will have

F_n = mg + Fsin\theta

now we know that the box will not move if applied force is balanced by frictional force on it

so we will have

Fcos\theta = \mu F_n

F cos\theta = \mu (mg + F sin\theta)

F(cos\theta - \mu sin\theta) = \mu mg

F = \frac{\mu mg}{cos\theta - \mu sin\theta}

so here we can say

cos\theta - \mu sin\theta > 0

tan\theta = \frac{1}{\mu}

\theta = tan^{-1}\frac{1}{\mu}

\theta = tan^{-1}(\frac{1}{0.43})

\theta = 66.7 degree

6 0
3 years ago
What current flow (I) is associated with an input voltage of 5.0V and resistors R1 = 1.5 kiloohms and R2 = 0.5 kiloohms? Calcula
Y_Kistochka [10]

Answer:

current in series is 2.50 mA

current in parallel is 13.51 mA

Explanation:

given data

voltage = 5 V

resistors R1 = 1.5 kilo ohms

resistors R2 = 0.5 kilo ohms

to given data

current flow

solution

current flow in series is express as here

current = voltage / resistor    .................1

put here all value  in equation 1

current = 5 / (1.5 + 0.5)

current = 5 / 2.0

so current = 2.50 mA

and

current flow in parallel is express as

current = voltage / resistor   ....................2

put here all value in equation  2

current = 5 / (1/ (1/1.5 + 1/0.5))

current = 5 / 0.37

so current = 13.31 mA

5 0
3 years ago
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