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salantis [7]
3 years ago
14

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS AND I NEED ALL CORRECT ANSWERS ONLY!!!

Physics
2 answers:
Kryger [21]3 years ago
7 0

Magnets are surrounded by magnetic fields.

Answer: last choice

valina [46]3 years ago
5 0

Magnets are surrounded by a magnetic force

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A centrifuge is used to test space pilots. The centrifuge spins with a centripetal acceleration of 3.04g. If the length of the a
uranmaximum [27]

Answer:

approx.= 25\frac{m}{s}

Explanation:

Centripetal acceleration (a) is defined as the square of an object's velocity (V^2) divided by the distance of the object from it's point/axis of revolution (r). So:

a=\frac{V^{2} }{r}

which allows us to solve for the velocity:

V=\sqrt{ar}\\ Since: a=3.04g=(3.04)(9.81),r=21;\\V=\sqrt{(3.04)(9.81)(21)} =25.02...

3 0
3 years ago
A Martian leaves Mars in a spaceship that is heading to Venus. On the way, the spaceship passes earth with a speed v = 0.80c rel
hjlf

To find the relative distance from one point to another it is necessary to apply the Relativity equations.

Under the concept of relativity the distance measured from a spatial object is given by the equation

l = l_0 \sqrt{1-\frac{v^2}{c^2}}

Where

l_0= Relative length

v = Velocity of the spaceship

c = Speed of light

Replacing with our values we have that

l = l_0 \sqrt{1-\frac{v^2}{c^2}}

l = 1.2*10^{11} \sqrt{1-\frac{0.8c^2}{c^2}}

l = 1.2*10^{11} \sqrt{1-0.8^2}

l = 7.2*10^{10}m

Therefore the distance between Mars and Venus measured by the Martin is 7.2*10^{10}m

8 0
2 years ago
?
vovangra [49]
Can you please post the picture of the graph and i will gladly answers it.
8 0
3 years ago
Read 2 more answers
What is the angle between P×Q and P±Q? 1) 0 2) PIE/2 3) PIE 4) 3PIE/2
faltersainse [42]

Answer:

option 2 is correct

Explanation:

the angle between p*q and p+q is 90 degree which is equal to π/2

it is rule that product of two vectors is always perpendicular to the plane in which both the vector lie

5 0
3 years ago
A spring is stretched from equilibrium to 0.90 m and the work done on the spring equals 18j what is the value of the spring cons
Stels [109]
Work done is given by 1/2kx^2
18 = 1/2*k*0.9*0.9
36 = k*0.81
44.4 = j/m^2
4 0
3 years ago
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